Tips for refining a list to only include items that contain every element from a specified array

Is there a way to search for all elements in an array and display them if they are all present? For instance, consider the following:

const data = [

  {
  "languages": ["JavaScript"],
    "tools": ["React", "Sass"]
  },
  
  {
  "languages": ["Python"],
    "tools": ["Vue", "Sass"]
  },
  
  {
  "languages": ["JavaScript"],
    "tools": ["Vue"]
  }

]


const newArr = ["Html","CSS"]
const newJobs = data.filter((item) => item.languages.includes(...newArr) || item.tools.includes(...newArr))

Although this solution provides results for each element, I am looking to evaluate all of them collectively.

(Please note that the code provided is just an example and the actual file contains more data, including Html and CSS)

Answer №1

If you want to filter out elements from the searchStrings array that match at least one element, you can use the some() method.

const data = [{
    "languages": ["JavaScript"],
    "tools": ["React", "Sass"]
  },

  {
    "languages": ["Python"],
    "tools": ["Vue", "Sass"]
  },

  {
    "languages": ["JavaScript"],
    "tools": ["Vue"]
  }
];


const searchStrings = ["Python", "React"];

const result = data.filter((item) => {
  return searchStrings.some((str) => {
    return item.languages.includes(str) || item.tools.includes(str);
  });
});

console.log(result); // Output will display the first 2 items from the array

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