Tips for optimizing your writing productivity with AngularJS ng-route to generate a large volume of pages

I need to add about 100 more pages to my code. Is there a shortcut to avoid writing the "when" statement 100 times? I want to simplify the code. Here is the existing code:

var module = angular.module("sampleApp", ['ngRoute']);

module.config(['$routeProvider',
    function($routeProvider) {
        $routeProvider.
            when('/route1', {
                templateUrl: 'angular-route-template-1.jsp',
                controller: 'RouteController'
            }).
            when('/route2', {
                templateUrl: 'angular-route-template-2.jsp',
                controller: 'RouteController'
            }).
            otherwise({
                redirectTo: '/'
            });
    }]);

module.controller("RouteController", function($scope) {

})

Answer №1

module.config(['$routeProvider', 'routes'

  function($routeProvider, routes) {
    // my custom routing configuration
    // defines the routes for the application

    routes.forEach(function(route) {
      $routeProvider.when(route.url, route.options);
    });

    $routeProvider.
    otherwise({
      redirectTo: '/'
    });
  }
]);

Answer №2

If you're looking for a cleaner way to achieve this, consider utilizing the ui-router module.

var app = angular.module('helloworld', ['ui.router']);

app.config(function($stateProvider) {
  var helloState = {
    name: 'hello',
    url: '/hello',
    template: '<h3>hello world!</h3>'
  }

  var aboutState = {
    name: 'about',
    url: '/about',
    template: '<h3>Its the UI-Router hello world app!</h3>'
  }

  $stateProvider.state(helloState);
  $stateProvider.state(aboutState);
});

To streamline your code, consider storing your 'state' objects in an array and iterating through them using the

$stateProvider.state(stateObject);
method.

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