Tips for invoking a reduce mechanism within a separate function

I need assistance with implementing a reduce function:

users.reduce(function (acc, obj) { return acc + obj.age/3; }, 0);   

within the following function structure:

function calculateUserAverageAge(users) {};

To analyze this array of objects and calculate the average of their "age" values:

const users = [{
           name: 'Brendan Eich',
           age: 56,
         }, {
           name: 'Linus Torvalds',
           age: 48,
         }, {
           name: 'Margaret Hamilton',
           age: 81,
         }];

Your guidance and support are greatly appreciated!

Answer №1

Simply reorganize your code within the function and then return the result.

Important: Instead of using 3, opt to use users.length instead.

In my opinion, it makes more sense mathematically to divide by the total number after summing them up, rather than dividing at each iteration.

const users = [{
  name: 'Brendan Eich',
  age: 56,
}, {
  name: 'Linus Torvalds',
  age: 48,
}, {
  name: 'Margaret Hamilton',
  age: 81,
}];

function computeUserAverageAge(users) {
  return Math.round(users.reduce((acc, obj) => acc + obj.age, 0) / users.length);
};

console.log(computeUserAverageAge(users))

Answer №2

It seems like the solution lies in returning the result of the reduce function. Using arrow functions can help simplify the code:

const getUserAverageAge = users => users.reduce((sum, { age }) => sum + age, 0) / 3;
console.log(getUserAverageAge(
  [{
    name: 'Brendan Eich',
    age: 56,
  }, {
    name: 'Linus Torvalds',
    age: 48,
  }, {
    name: 'Margaret Hamilton',
    age: 81,
  }]
));

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