Tips for eliminating the empty element from a JavaScript array

Here is the code implementation I am working with:

Array.prototype.abc = function(condition, t){
    var arr = [];
    for( var i = 0; i < this.length; i++){
        arr.push(condition(this[i],t));         
    }
    return arr;
};

var a = [1,2,3,4];
var t = 2;

alert(a.abc( function(item,diviser){
    if(item % diviser === 0) { return item; }
},t));

My expected result should be [2,4]. However, I am getting [,2,,4].

I attempted different conditions to prevent empty values in the array like below:

if(condition(this[i],t) !== false){ arr.push(condition(this[i],t)); }

I tried returning false or true from the else part when I perform the check on items. Interestingly, no matter what value I return, I still end up with blank sections in the array. Even without using the else part, blank spaces persist. I am aware that I can use splice to remove these blanks, but I am puzzled as to why they are being created in the first place. How can I avoid these blank elements in my array?

Answer №1

Before proceeding, it is crucial to verify if the value being returned from your callBack function is truly undefined,

for( var i = 0; i < this.length; i++){
  var x = checkCondition(this[i],t);
  if(typeof x !== "undefined") filteredArray.push(x);         
}

You attempted multiple fixes, however, they are ineffective due to the following reasons:

  1. The comparison !== false will always evaluate to false because your callBack can only return a number or undefined. This type mismatch leads to consistent failure of strict equality check.

  2. In the code snippet

    if(item % divisor === 0) { return item; } else { return false; }
    , when the condition is not met, false will be returned resulting in pushing false into the array rather than skipping that action.

Answer №2

Before adding an element to the array, move the condition outside of the push and ensure that it only evaluates to true or false.

if (checkCondition(this[i], t)) {
    arr.push(this[i]);         
}

Answer №3

This is occurring because you are executing a push regardless of the value returned by the condition.

Make this change

arr.push(condition(this[i],t));

to

var val = condition(this[i],t)
val = val !== false && arr.push(val);

As the condition function always explicitly returns false, checking for val !== false is sufficient.

DEMO

Array.prototype.abc = function(condition, t){
    var arr = [];
    for( var i = 0; i < this.length; i++){
       var val = condition(this[i],t); console.log(val);
       val !== false && arr.push(val);
    }
    return arr;
};

var a = [1,2,3,4];
var t = 2;

document.body.innerHTML += a.abc( function(item,diviser){
    if(item % diviser === 0) { return item; } else { return false; }
},t);

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