Tips for eliminating duplicate words and potentially incorporating new terms into a text

Question

Tips for eliminating duplicate words and potentially incorporating new terms into a text

Is there a way to eliminate specific words that are repeated exactly twice in a string, and if possible, add the word "and"? This should only apply to certain characters.

For instance, take the following example: "Intruction in seated LE AROM x10 each instruction in standing LE AROM x10 each."

The desired outcome is: "Instruction in seated LE AROM and standing LE AROM x10 each".

I attempted various methods such as looping through the string and removing duplicates, but it caused me to lose needed information. I also experimented with a solution from another individual's query, although they were focused on counting occurrences of a word rather than my particular issue.

function removeDuplicate(str) {
   let words = JSON.stringify(str).toLowerCase().split(' ')
    
    let wordsCount = {}

    words.forEach(word => {
        wordsCount[word] = (wordsCount[word] || 0) + 1
    })
    
}

javascript arrays count

Answer 1

Answer №1

Your provided example contradicts the explanations you have given.

You mentioned that "Instruction" is only removed once, while 'x10' and 'each' are removed twice. What exactly should 'and' replace in this scenario?

If your goal is to replace "x10 each" with "and", there is a JavaScript method available for that:

const initial = 'Instruction in seated LE AROM x10 each instruction in standing LE AROM x10 each';
const wished = initial.replaceAll('x10 each', 'and');
// Instruction in seated LE AROM and instruction in standing LE AROM and

If you wish to replace words that appear twice with 'end', you can utilize the filter and includes methods:

const initial = 'Instruction in seated LE AROM x10 each instruction in standing LE AROM x10 each';
const toRemove = ['x10', 'each'];

function removeDuplicate(str, arr, repl) {
    const words = str.toLowerCase().split(' ');
    let wished = str;

    words.forEach(word => {
        if (words.filter(elem => elem === word).length === 2 && arr.includes(word)) {
            wished = wished.replaceAll(word, repl);
        }
    });

    return wished;
}
// Instruction in seated LE AROM and and instruction in standing LE AROM and and

It appears that you may be looking for a different solution.

Answer 2

Your provided example contradicts the explanations you have given.

You mentioned that "Instruction" is only removed once, while 'x10' and 'each' are removed twice. What exactly should 'and' replace in this scenario?

If your goal is to replace "x10 each" with "and", there is a JavaScript method available for that:

const initial = 'Instruction in seated LE AROM x10 each instruction in standing LE AROM x10 each';
const wished = initial.replaceAll('x10 each', 'and');
// Instruction in seated LE AROM and instruction in standing LE AROM and

If you wish to replace words that appear twice with 'end', you can utilize the filter and includes methods:

const initial = 'Instruction in seated LE AROM x10 each instruction in standing LE AROM x10 each';
const toRemove = ['x10', 'each'];

function removeDuplicate(str, arr, repl) {
    const words = str.toLowerCase().split(' ');
    let wished = str;

    words.forEach(word => {
        if (words.filter(elem => elem === word).length === 2 && arr.includes(word)) {
            wished = wished.replaceAll(word, repl);
        }
    });

    return wished;
}
// Instruction in seated LE AROM and and instruction in standing LE AROM and and

It appears that you may be looking for a different solution.

Answer 3

Answer №2

One way to track how often a specific word appears in a string is by using a counter, allowing you to then access the word based on its key or value. From there, you can decide which words to keep or remove using an if(){}else{} statement or even a switch statement.

It can be challenging to identify which words you want to keep if they appear multiple times in the array of words.

To address this, you can create a count of each word's occurrences and then selectively remove certain words from the array "arrToChange" based on your criteria, before converting the updated array back into a string.

            let originalString = "Instruction in seated LE AROM x10 each instruction in standing LE AROM x10 each";

            /* Within arrToChange, you have the option to eliminate words by their corresponding indexes in arr (uppercase), allowing you to maintain the original wording as it appears in the initial string.*/

            const arrToChange = originalString.split(" ");
            const arr = originalString.toUpperCase().split(" ");
            const counts = {};

            for (const num of arr) {
                if(counts[num]){
                    counts[num] ++;
                }else{
                    counts[num] = 1;
                }
            }
            
            console.log("arrToChange = " + arrToChange);
            console.log("arr = " + arr);
            console.log("Object counts = ");
            console.log(counts);
            
            console.log("Object.keys   = " + Object.keys(counts));
            console.log("Object.values = " + Object.values(counts));
            
            // If you prefer an Array of Arrays
            // This will provide you with an array structured like so:
            // [["Intruction",1],["in",2],["seated",1],...]
            console.log("");
            console.log("console.log(Object.entries(counts)); =>");
            console.log(Object.entries(counts));

By counting the occurrences and identifying the words to remove within the array arrToChange, you simply need to locate the indexes of these words for deletion...

Answer 4

One way to track how often a specific word appears in a string is by using a counter, allowing you to then access the word based on its key or value. From there, you can decide which words to keep or remove using an if(){}else{} statement or even a switch statement.

It can be challenging to identify which words you want to keep if they appear multiple times in the array of words.

To address this, you can create a count of each word's occurrences and then selectively remove certain words from the array "arrToChange" based on your criteria, before converting the updated array back into a string.

            let originalString = "Instruction in seated LE AROM x10 each instruction in standing LE AROM x10 each";

            /* Within arrToChange, you have the option to eliminate words by their corresponding indexes in arr (uppercase), allowing you to maintain the original wording as it appears in the initial string.*/

            const arrToChange = originalString.split(" ");
            const arr = originalString.toUpperCase().split(" ");
            const counts = {};

            for (const num of arr) {
                if(counts[num]){
                    counts[num] ++;
                }else{
                    counts[num] = 1;
                }
            }
            
            console.log("arrToChange = " + arrToChange);
            console.log("arr = " + arr);
            console.log("Object counts = ");
            console.log(counts);
            
            console.log("Object.keys   = " + Object.keys(counts));
            console.log("Object.values = " + Object.values(counts));
            
            // If you prefer an Array of Arrays
            // This will provide you with an array structured like so:
            // [["Intruction",1],["in",2],["seated",1],...]
            console.log("");
            console.log("console.log(Object.entries(counts)); =>");
            console.log(Object.entries(counts));

By counting the occurrences and identifying the words to remove within the array arrToChange, you simply need to locate the indexes of these words for deletion...

Answer 5

Answer №3

Understanding your intentions can be a bit challenging. Here is my best attempt based on the information provided:

const orig = "Instruction in seated LE AROM x10 each instruction in standing LE AROM x10 each"
const re = /\b(.+)(\s.*?\s)(.+)\s.*?\1(.*?)\3/
const result = orig.replace(re, '$1$2and$4$3')
console.log(result)
// => Instruction in seated and standing LE AROM x10 each

The regular expression will capture the following patterns:

( in)( seated )(LE AROM x10 each) instruction{ in}( standing ){LE AROM x10 each}

By using .replace, the sentence is rearranged with the captures and the word "and" added:

( in)( seated )and( standing )(LE AROM x10 each)

If you need to repeat "LE AROM," you can explicitly include it in the pattern like this:

const orig = "Instruction in seated LE AROM x10 each instruction in standing LE AROM x10 each"
const re = /\b(.+)(\s.*? LE AROM\s)(.+)\s.*?\1(.*?)\3/
const result = orig.replace(re, '$1$2and$4$3')
console.log(result)
// => Instruction in seated LE AROM and standing LE AROM x10 each

Alternatively, if "LE AROM" is all uppercase and needs to be repeated, you can restrict uppercase letters in the third group:

const orig = "Instruction in seated LE AROM x10 each instruction in standing LE AROM x10 each"
const re = /\b(.+)(\s.*?\s)([^A-Z]+)\s.*?\1(.*?)\3/
const result = orig.replace(re, '$1$2and$4$3')
console.log(result)
// => Instruction in seated LE AROM and standing LE AROM x10 each

Answer 6

Understanding your intentions can be a bit challenging. Here is my best attempt based on the information provided:

const orig = "Instruction in seated LE AROM x10 each instruction in standing LE AROM x10 each"
const re = /\b(.+)(\s.*?\s)(.+)\s.*?\1(.*?)\3/
const result = orig.replace(re, '$1$2and$4$3')
console.log(result)
// => Instruction in seated and standing LE AROM x10 each

The regular expression will capture the following patterns:

( in)( seated )(LE AROM x10 each) instruction{ in}( standing ){LE AROM x10 each}

By using .replace, the sentence is rearranged with the captures and the word "and" added:

( in)( seated )and( standing )(LE AROM x10 each)

If you need to repeat "LE AROM," you can explicitly include it in the pattern like this:

const orig = "Instruction in seated LE AROM x10 each instruction in standing LE AROM x10 each"
const re = /\b(.+)(\s.*? LE AROM\s)(.+)\s.*?\1(.*?)\3/
const result = orig.replace(re, '$1$2and$4$3')
console.log(result)
// => Instruction in seated LE AROM and standing LE AROM x10 each

Alternatively, if "LE AROM" is all uppercase and needs to be repeated, you can restrict uppercase letters in the third group:

const orig = "Instruction in seated LE AROM x10 each instruction in standing LE AROM x10 each"
const re = /\b(.+)(\s.*?\s)([^A-Z]+)\s.*?\1(.*?)\3/
const result = orig.replace(re, '$1$2and$4$3')
console.log(result)
// => Instruction in seated LE AROM and standing LE AROM x10 each

Tips for eliminating duplicate words and potentially incorporating new terms into a text

Answer №1

Answer №2

Answer №3

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