Tips for Avoiding Inheritance of a Specific Method

Let's say we have two classes, A and B. Class B extends class A, inheriting all of its methods. It is also possible to override these inherited methods. The question at hand is whether it is possible to prevent class B from inheriting a specific method of class A. Here is the approach taken so far:

// setting up
class A {
  constructor(x) {
    this.x = x;
  }

  valueOf() {
    return this.x;
  }

  toString() {
    return `{x:${this.x}}`;
  }
}

class B extends A {
  constructor(x) {
    super(x);
    delete this.valueOf;
  }
}

delete B.prototype.valueOf;

// example
const a = new A(42);
const b = new B(42);

// expected behavior
console.log(a.valueOf());
// should throw TypeError as valueOf should not be inherited
console.log(b.valueOf());

Answer №1

There have been a few individuals who have already shared potential solutions for your problem. However, I would like to present an alternative perspective. :-)

Inheritance is designed to represent an IS-A relationship or more specifically, an IS-SUBSTITUTABLE-FOR-A relationship. This concept is encapsulated in the Liskov Substitution Principle (the "L" in SOLID).

The idea behind this principle is that any code meant to work on an object of type "A" should seamlessly operate on an object of type "B" as well ("A" can be substituted with "B") without encountering any issues. If "B" lacks certain methods or fails to provide the complete interface of "A", then it ceases to be substitutable. In such cases, inheritance may not be the ideal solution.

Answer №2

It's interesting to note that using valueOf as an example may not be the best choice since every object inherits it from Object.prototype. To see this in action, try running console.log(({}).valueOf())

However, there is a clever workaround by hiding this property.

// customized setup
class A {
  constructor(x) {
    this.x = x;
  }

  valueOf() {
    return this.x;
  }

  toString() {
    return `{x:${this.x}}`;
  }
}

class B extends A {
   get valueOf() { return undefined; }
}

class C extends A {
}

Object.defineProperty(C.prototype, 'valueOf', {})

// demonstration
const a = new A(42);
const b = new B(42);
const c = new C(42);

// expected output
console.log(a.valueOf());
// TypeError should be thrown instead of returning a function
try {
  console.log(b.valueOf());
} catch (e) {
  console.log(e.message);
}

// catching potential error
try {
  console.log(c.valueOf());
} catch (e) {
  console.log(e.message);
}

Answer №3

Removing the valueOf property using delete this.valueOf
and delete B.prototype.valueOf is ineffective because there is no such valueOf property to delete in the first place. Inheritance operates by searching the prototype chain when a property is not found within the object itself, rather than duplicating properties from the parent.

To prevent following the chain, you can instead assign a value to this.valueOf:

this.valueOf = null;

This will result in an error indicating that null is not a function.

Alternatively, instead of implementing this change individually for each object, it can be applied to the B prototype:

B.prototype.valueOf = null;

Answer №4

It is important to note that in JavaScript, inheritance involves inheriting from the prototype object rather than individual properties. When you inherit from an object, you inherit all of its properties as a whole.

While it is possible to override inherited properties, deleting them is not recommended as it would require modifying the prototype object. Instead, you can effectively "shadow" a property by assigning it an undefined value:

class Parent {
  constructor(value) {
    this.value = value;
  }

  getValue() {
    return this.value;
  }
}

class Child extends Parent {
}
Child.prototype.getValue = undefined;

Answer №5

In the scenario you provided, B does not inherit from A directly; instead, it inherits certain aspects of A. This subset of characteristics serves as the common ancestor, suggesting a potential refactoring where both A and B inherit from a shared class X.

Alternatively, you could modify the function within B to explicitly throw an error, although that may not align with your objective. In modern Javascript development, there is a trend towards using composition to generate classes with identical functionality but distinct implementation details.

Consider this revised approach using composition:

const ValueProto = {
  getValue() {
    return this.x
  }
}

const StringProto = {
  toString() {
    return `{x:${this.x}}`;
  }
}

const ClassA = (x) => Object.assign({}, ValueProto, StringProto, {x});
const ClassB = (x) => Object.assign({}, StringProto, {x});

const object1 = ClassA(5)
console.log(object1.toString()) // 'x:5'
console.log(object1.getValue()) // 5


const object2 = ClassB('hello')
console.log(object2.toString()) // 'x:hello'
console.log(object2.getValue()) // not a function

This example offers a glimpse into one method of implementing composition, although various models exist, such as those leveraging the Class object.

Answer №6

@Bergi has already provided an explanation for why inheritance may not be the most suitable tool for dealing with types that require customization.

Instead, what is needed are techniques based on mixins for composing behaviors. In the specific example given, traits would be particularly beneficial as they allow for composition of behavior with options for overwriting, aliasing, omitting, and even modifying it while incorporating both traits and classes.

Given that JavaScript lacks support for traits, a solution resembling traits could involve utilizing patterns such as functions and proxy objects through closures, delegation via apply/call, and forwarding. For reference, a possible approach similar to this can be found in the response linked here.

In relation to the example code shared by the original poster, an implementation considering some of the mentioned techniques and mixin-patterns might look like the following:

function withFullyExposeX() {   
  this.valueOf = function () {
    return this.x; 
  };                           
  this.toString = function () {
    return `{x:${this.x}}`;    
  };                            
}                               

var withExposeXValueAndShadowXStringify = (function (mixin) {
  return function () {
    mixin.call(this);                  
    this.toString = function () {};     
  };
}(withFullyExposeX));

var withProxyOnlyExposesValueOfX = (function (mixin) {  
  var localProxy = {};                                   
  mixin.call(localProxy);                              
                                                       
  return function () {                                  
    this.valueOf = function () {                        
      return localProxy.valueOf.call(this);             
    };                                                  
  }                                                     
}(withFullyExposeX));                                   


class X {
  constructor(x) {
    this.x = x;
  }
}

class A extends X {}
withFullyExposeX.call(A.prototype);   

class B extends X {}
withExposeXValueAndShadowXStringify.call(B.prototype);

class C extends X {}
withProxyOnlyExposesValueOfX.call(C.prototype);

var
  x = new X('x'),

  a = new A('a'),
  b = new B('b'),
  c = new C('c');

console.log('x.valueOf : ', x.valueOf);
console.log('a.valueOf : ', a.valueOf);
console.log('b.valueOf : ', b.valueOf);
console.log('c.valueOf : ', c.valueOf);

console.log('x.valueOf() : ', x.valueOf());
console.log('a.valueOf() : ', a.valueOf());
console.log('b.valueOf() : ', b.valueOf());
console.log('c.valueOf() : ', c.valueOf());

console.log('x.toString : ', x.toString);
console.log('a.toString : ', a.toString);
console.log('b.toString : ', b.toString);
console.log('c.toString : ', c.toString);

console.log('x.toString() : ', x.toString());
console.log('a.toString() : ', a.toString());
console.log('b.toString() : ', b.toString());
console.log('c.toString() : ', c.toString());
.as-console-wrapper { max-height: 100%!important; top: 0; }

Answer №7

Check out this clever solution for removing unnecessary properties from the derived constructor:

class Human {
    constructor(name, surname, years){
        //console.log(arguments);
        this.name = name;
        this.surname = surname;
        this.years = years;

    }
}

const person = new Human('John', 'Doe', 30);
console.log(person);

class Employee extends Human {
    constructor(surname, years, jobTitle){
    super(name,surname, years);
    delete this.name;
    this.jobTitle = jobTitle;
}
}


const employee = new Employee('Doe', 30, 'Software Engineer');
console.log(employee);

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