There was an error caught: the object is not a function, specifically the button inside a form

Question

There was an error caught: the object is not a function, specifically the button inside a form

Here is a snippet of code from my jsp page:

<form name="programarRutasForm" method="post" action="/SGT_Galp_web/programarRutas.do">   
     <table>
        <tr>
          <td>
            <input type="button" name="insereVuelta" value="Insere Vuelta" onclick="insereVuelta()" id="insereVuelta">
          </td>
          <td>
            <input type="submit" name="criaRuta" value="Cria Ruta" id="criaRuta">
          </td>
        </tr>
     </table>
     ...

After clicking the button insereVuelta, an exception appears with the message:

Uncaught TypeError: object is not a function

However, when I move the button outside the form, everything works fine. Why is this happening? I really need to keep the button next to the submit button inside the form.

javascript forms exception button

Answer 1

Answer №1

In my opinion, the issue arises from having both the function and button share the same name. I encountered a similar problem and was able to resolve it by renaming the button. It seems like you also found success in resolving the issue by changing the name of your button.

Speculation:

My theory is that when the names match, the interpreter attempts to reference the button instead of the function. Since the button is not a function, it results in an error being thrown.

As for why it worked for you when the button was placed outside the form, I don't have a definitive explanation. It could be possible that placing the button outside the form prevents the interpreter from automatically linking it as an accessible object, or it may require being accessed through a "parent" element.

Answer 2

In my opinion, the issue arises from having both the function and button share the same name. I encountered a similar problem and was able to resolve it by renaming the button. It seems like you also found success in resolving the issue by changing the name of your button.

Speculation:

My theory is that when the names match, the interpreter attempts to reference the button instead of the function. Since the button is not a function, it results in an error being thrown.

As for why it worked for you when the button was placed outside the form, I don't have a definitive explanation. It could be possible that placing the button outside the form prevents the interpreter from automatically linking it as an accessible object, or it may require being accessed through a "parent" element.

Answer 3

Answer №2

The issue stems from missing semi-colons in your script. Double check for any lines that lack semi-colons. You may be wondering, "but why does it work outside the form?" This could be due to Automatic Semicolon insertion behaving differently in certain scenarios. For more information on this topic, refer to: What are the rules for JavaScript's automatic semicolon insertion (ASI)?

Implementing these changes should resolve the error.

Answer 4

The issue stems from missing semi-colons in your script. Double check for any lines that lack semi-colons. You may be wondering, "but why does it work outside the form?" This could be due to Automatic Semicolon insertion behaving differently in certain scenarios. For more information on this topic, refer to: What are the rules for JavaScript's automatic semicolon insertion (ASI)?

Implementing these changes should resolve the error.

Answer 5

Answer №3

The identifier insereVuelta is utilized for the input's name and ID, as well as the function name. Consider modifying either the name and ID or the function name.

Answer 6

The identifier insereVuelta is utilized for the input's name and ID, as well as the function name. Consider modifying either the name and ID or the function name.

There was an error caught: the object is not a function, specifically the button inside a form

Answer №1

Answer №2

Answer №3

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