I'm currently attempting to tackle a challenging binary gap issue using regex, but I've hit a roadblock with it.
If I use the following code snippet:
Number(101001000).toString().match(/(1[0]+1)/g)
It only returns ["101"], whereas I was hoping for
["101", "1001"]Could there be an error in my approach or is achieving this outcome solely through regex not feasible?
function findBinaryGaps(binaryStr) {
return (
binaryStr
.split("1")
.reduce((accumulator, currentValue, index, array) => {
if(index && index < array.length-1)
accumulator.push(1 + currentValue + 1);
return accumulator;
}, [])
);
}
console.log(findBinaryGaps(Number(101001000).toString()));
console.log(findBinaryGaps("00101001000"));
console.log(findBinaryGaps("001010011000"));To achieve this using only regex, it's important not to include the terminating 1 in the match result, as it might be needed for a subsequent match.
Instead, ensure that there is a 1 immediately following the match without capturing it.
If you want to retain the ending 1 in the output, adjust the match result accordingly:
console.log(
(101001000).toString().match(/10+(?=1)/g).map(m => m + "1")
)Some additional points to consider:
It is unnecessary to use the Number function since 101001000 is already a number. The extra step is mainly needed to clarify the dot in .toString(). Simply adding parentheses resolves the ambiguity. Another option is to add an extra dot: 101001000..toString() will also work.
Square brackets are not required around 0 in your regex, nor do you need to enclose the entire expression in parentheses.
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