The sequence in which arguments are executed in the console.log() function

After running tests on both CodeAcademy's editor and Chrome's console, I came across an interesting observation. I noticed that the argument of console.log() is not evaluated first even if it is an expression. Why does this happen?

var x = 0;
console.log(x++);  // displays 0 instead of 1
console.log(x);  // displays 1

Answer №1

x++ is a shorthand for using the value of x and then incrementing it by one. In this case, the console will log the current value of x (which is 0) and then increment it to 1. If you want to increment x before using its value, you can use the prefix operator ++ like this:

var x = 0;

console.log(++x);
console.log(x);

Answer №2

The operator at the end of the code is a postfix operator, meaning it will only be incremented after the function has finished executing.

If you want to modify the value before it prints, you can use the prefix operator: ++x.

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