The process of reversing an array is not fully completing due to the pop method being used within a loop

Question

The process of reversing an array is not fully completing due to the pop method being used within a loop

Note: I've been immersed in code for hours now and have reached a stage where I'm starting to doubt the spelling of every word or question if I have dyslexia. Despite this, I know this should be a simple question.

I want to create a basic function (without relying on the standard JavaScript reverse method) that, when given an array, generates a new array with the same values but in reverse order.

Why does the current function remove "C" and "B", but not "A"?

function reverseArray(arr) {
    var reversedArr = [];
    for (var i = 0; i < arr.length; i++) {
        var popped = arr.pop(i);
        reversedArr.push(popped);
    }
    return reversedArr;
}

console.log(reverseArray(["A", "B", "C"]));

Even though the expected outcome is ["C", "B", "A"], it's actually showing only → ["C", "B"]. When I check the array within the function, "A" is still present.

To solve this, I've included

reversedArr.push(arr.pop(arr[0]));

after the for loop and before the return statement. This resolves the issue, but considering that the for loop should continue while i is less than the array length and when the array only contains "A", where the length is 1 and i is 0, shouldn't it also remove "A"?

What am I overlooking here?

javascript arrays methods

Answer 1

Answer №1

Removing an element from an array using the pop method will permanently delete the item and adjust the length of the array. More information can be found here

In your code, it is recommended to use:

var removedItem = arr[i];

And implement reverse iteration as shown below:

for (var i = arr.length - 1; i >= 0; i--)

Answer 2

Removing an element from an array using the pop method will permanently delete the item and adjust the length of the array. More information can be found here

In your code, it is recommended to use:

var removedItem = arr[i];

And implement reverse iteration as shown below:

for (var i = arr.length - 1; i >= 0; i--)

Answer 3

Answer №2

Give this a shot,

function reverseArray(arr) {
  var reversedArr = [];
  while (arr.length > 0) {
    reversedArr.push(arr.pop())
  }
  return reversedArr;
}

What is the logic behind this?

pop removes the last element in the array without needing an index. Simply keep popping elements until the array is empty.

Answer 4

Give this a shot,

function reverseArray(arr) {
  var reversedArr = [];
  while (arr.length > 0) {
    reversedArr.push(arr.pop())
  }
  return reversedArr;
}

What is the logic behind this?

pop removes the last element in the array without needing an index. Simply keep popping elements until the array is empty.

Answer 5

Answer №3

Solution implemented with the pop method.

function reverseArray(arr) {
    var loopNumber = arr.length 
    var reversedArr = [];
    for (var i = 0; i < loopNumber; i++) {
        var popped = arr.pop();
        reversedArr.push(popped);
    }
    return reversedArr;
}

console.log(reverseArray(arr));

Answer 6

Solution implemented with the pop method.

function reverseArray(arr) {
    var loopNumber = arr.length 
    var reversedArr = [];
    for (var i = 0; i < loopNumber; i++) {
        var popped = arr.pop();
        reversedArr.push(popped);
    }
    return reversedArr;
}

console.log(reverseArray(arr));

The process of reversing an array is not fully completing due to the pop method being used within a loop

Answer №1

Answer №2

Answer №3

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