This function always results in an empty array.
Here is a JavaScript implementation for solving the two sum problem:
function twoSum(nums, target) {
const map = {};
for (let i = 0; i < nums.length; i++) {
let comp = target - nums[i];
if (map[comp] !== undefined) {
return [map[comp], i];
} else {
map[comp] = i;
}
}
return [];
}
console.log(twoSum([2, 7, 11, 15], 9));Kindly review the information provided below:
function findTwoSum(nums, target) {
const numsMap = {};
for(let i = 0; i < nums.length; i++) {
const num = nums[i];
const complement = target - num;
if(numsMap[complement] !== undefined) {
return [numsMap[complement], i];
}
numsMap[num] = i;
}
}
const nums = [2,7,11,15];
const target = 9;
const resultIndices = findTwoSum(nums, target);
console.log(resultIndices); // [0,1]
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