The Javascript executor in Selenium is delivering a null value

My JavaScript code is causing some issues when executed with Selenium's JavascriptExecutor. Strangely, the code returns null through Selenium but a value in Firefox developer console.

function temp(){
    var attribute = jQuery(jQuery("[name='q']")[0]).attr('type');
    if(typeof attribute !== 'undefined' && attribute !== false){
        return attribute;
    } else {
        return '';
    }
}

temp();

Here's my WebDriver code using the same JS function:

JavascriptExecutor jsExecutor = (JavascriptExecutor)driver;
Object inputType = 
       jsExecutor.executeScript("function temp(){...}temp();");
System.out.println("Type: " + inputType);

Instead of getting the expected "text" string, I'm only getting null. Any ideas on what could be causing this?

javascriptseleniumnullpointerexceptionselenium-webdriver

Answer №1

Make sure to utilize return tmp() rather than just tmp() when using the executeScript() method. For more information, refer to driver.executeScript() returns NullPointerException for simple JavaScript

Answer №2

Make sure to include a return statement within the jsExec.executeScript(...) function in order to properly return the desired result.

Answer №3

The issue arises from attempting to execute two statements within the executeScript() method - both defining the function tmp() and calling it.

While the specifics are unclear, it appears that the function definition may be returning null.

Because executeScript only returns the first potential return value encountered, in this case null is returned since the function definition comes first. To resolve this, consider not defining the function separately and instead writing the code directly inline.

JavascriptExecutor jsExec = (JavascriptExecutor) driver;
Object inpType = jsExec
    .executeScript("var attrb = jQuery(jQuery(\"[name='q']\")[0]).attr('type');"+
            "if(typeof attrb !== 'undefined' && attrb !== false)" +
            "{return attrb;}" +
            "else{return '';}");
System.out.println("-------------- Type: " + inpType);

This modification should output your expected value as intended.

Edit: Additionally, ensure that the "" around [name='q'] in your posted code is properly escaped to avoid prematurely ending the string and causing syntax errors.

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