Execute the code snippet below in Chrome console and observe the printed output. Why does the console log still get displayed even after an error is thrown by the f2() function?
async function f1() {
const p = await f2();
console.log("This line should not get printed since the promise was rejected");
}
async function f2() {
Promise.reject("promise rejected");
}
f1();
One common issue is arising due to the inadequate handling of Promise rejection from the f2() function. When the
Promise.reject("promise rejected")To address this and similar issues effectively, incorporating try-catch blocks for handling side effects is recommended. Here's how you can modify your code:
async function f1() {
try {
const p = await f2();
console.log("This line should not get printed since the promise was rejected");
} catch (error) {
console.error(error); // You have the option to omit logging any information
}
}
async function f2() {
return Promise.reject("promise rejected");
}
f1();
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