The error message reads: "Task function must be provided in Gulp"

I am new to using Gulp and I am in the process of creating a gulpfile to minify and merge css and js files. However, when I try to run the command gulp, I encounter the following error:

C:\Users\S.Hocine\Desktop\gulpTest>gulp
AssertionError [ERR_ASSERTION]: Task function must be specified
    at Gulp.set [as _setTask] (C:\Users\S.Hocine\Desktop\gulpTest\node_modules\undertaker\lib\set-task.js:10:3)
    at Gulp.task (C:\Users\S.Hocine\Desktop\gulpTest\node_modules\undertaker\lib\task.js:13:8)
    at Object.<anonymous> (C:\Users\S.Hocine\Desktop\gulpTest\gulpfile.js:36:6)
    at Module._compile (internal/modules/cjs/loader.js:1156:30)
    at Object.Module._extensions..js (internal/modules/cjs/loader.js:1176:10)
    at Module.load (internal/modules/cjs/loader.js:1000:32)
    at Function.Module._load (internal/modules/cjs/loader.js:899:14)
    at Module.require (internal/modules/cjs/loader.js:1042:19)
    at require (internal/modules/cjs/helpers.js:77:18)
    at requireOrImport (C:\Users\S.Hocine\AppData\Roaming\npm\node_modules\gulp-cli\lib\shared\require-or-import.js:19:11) {
  generatedMessage: false,
  code: 'ERR_ASSERTION',
  actual: false,
  expected: true,
  operator: '=='
}

Here is my gulpfile:

const gulp = require('gulp');
const uglify = require('gulp-uglify');
const concat = require('gulp-concat');

// Minify and copy html
gulp.task('minifyHtml', function(){
    gulp.src('src/*.html')
        .pipe(uglify())
        .pipe(gulp.dest('dest'));
  });

// Minify and merge css
gulp.task('minifyMergeCss', function(){
    gulp.src('src/css/*.css')
        .pipe(concat('merged-min.css'))
        .pipe(uglify())
        .pipe(gulp.dest('dest/css'));
  });

// Minify and merge js
gulp.task('minifyMergeJs', function(){
  gulp.src('src/js/*.js')
      .pipe(concat('merged-min.js'))
      .pipe(uglify())
      .pipe(gulp.dest('dest/js'));
});

gulp.task('default', ['minifyHtml', 'minifyMergeCss', 'minifyMergeJs']);

gulp.task('watch', function(){
  gulp.watch('src/*.html', ['minifyHtml']);  
  gulp.watch('src/css/*.css', ['minifyMergeCss']);
  gulp.watch('src/js/*.js', ['minifyMergeJs']);
});

My gulp version:
CLI version: 2.3.0
Local version: 4.0.2

Can you help me identify the problem?

Answer №1

If you are using gulp version V3 with a different syntax, make sure to update to the latest version of gulp. Also, ensure that the gulp task modules you are using are up-to-date. If they still don't work, try this approach:

For example, your function should look like this,

    gulp.task('default', gulp.series('minifyHtml', 'minifyMergeCss', 'minifyMergeJs'));

This will now work properly because the list parameter has been deprecated in gulp v4.

For a more comprehensive example, check out the gulp documentation on running tasks in series

Alternatively, refer to the documentation on npm

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