The error message "ch.match is not a function" appeared in the Javascript code

Question

The error message "ch.match is not a function" appeared in the Javascript code

Here are two functions that I need help with:

//Function A
var ltrToNato = function(ch) {
  var x = ch;
  var nato =
    ('{"A": "Alpha", "B": "Bravo", "C": "Charlie", "D": "Delta", "E": "Echo", "F": "Foxtrot", "G": "Golf", "H": "Hotel", "I": "India", "J": "Juliet", "K": "Kilo",
  "L": "Lima", "M": "Mike", "N": "November", "O": "Oscar", "P": "Papa", "Q": "Quebec", "R": "Romeo", "S": "Sierra", "T": "Tango", "U": "Uniform", "V": "Victor",
  "W": "Whiskey", "X": "X-Ray", "Y": "Yankee", "Z": "Zulu", "0" : "Zero", "1" : "One", "2" : "Two", "3" : "Three", "4" : "Four", "5" : "Five", "6" : "Six",
   "7" : "Seven", "8" : "Eight", "9" : "Niner"}');
  var natoLower = nato.toLowerCase();
  var natoAlpha = JSON.parse(nato);
  var natoAlphaLower = JSON.parse(natoLower);
  if (ch >= "A" && ch <= "Z")
    return natoAlpha[ch];
  else if (ch >= "a" && ch <= "z")
    return natoAlphaLower[ch];
  else if (x = x.match(/[0-9]/g))
    return natoAlpha[ch];
  else
    return x;
}

//Function B
var wordToNato1 = function(str) {
  var s = "";
  for (var i = 0; i <= str.length; i++) {
    s + ltrToNato(i);
  }
}

The first function successfully converts letters and numbers to their Nato form. The issue arises with the second function which aims to convert a string into its Nato equivalent. When trying to execute wordToNato, an error message is displayed:

ch.match is not a function

I am unsure of what is causing this error. Any assistance would be greatly appreciated.

javascript json function

Answer 1

Answer №1

Can you help clarify something for me?

I am looking to transform letters into words based on a pre-defined mapping.

To achieve this, all you need to do is break down the input into individual characters. Then, use the mapping provided to convert each character into its corresponding word and finally join them all together with a space in between.

var MAP ={A:"Alpha",B:"Bravo",C:"Charlie",D:"Delta",E:"Echo",F:"Foxtrot",G:"Golf",H:"Hotel",I:"India",J:"Juliet",K:"Kilo",L:"Lima",M:"Mike",N:"November",O:"Oscar",P:"Papa",Q:"Quebec",R:"Romeo",S:"Sierra",T:"Tango",U:"Uniform",V:"Victor",W:"Whiskey",X:"X-Ray",Y:"Yankee",Z:"Zulu",0:"Zero",1:"One",2:"Two",3:"Three",4:"Four",5:"Five",6:"Six",7:"Seven",8:"Eight",9:"Niner"};


function strToNato(str){
    return str.toUpperCase().split('').map(l => MAP[l] || l).join(' ');
}

console.log(strToNato('ABC123'));

Answer 2

Can you help clarify something for me?

I am looking to transform letters into words based on a pre-defined mapping.

To achieve this, all you need to do is break down the input into individual characters. Then, use the mapping provided to convert each character into its corresponding word and finally join them all together with a space in between.

var MAP ={A:"Alpha",B:"Bravo",C:"Charlie",D:"Delta",E:"Echo",F:"Foxtrot",G:"Golf",H:"Hotel",I:"India",J:"Juliet",K:"Kilo",L:"Lima",M:"Mike",N:"November",O:"Oscar",P:"Papa",Q:"Quebec",R:"Romeo",S:"Sierra",T:"Tango",U:"Uniform",V:"Victor",W:"Whiskey",X:"X-Ray",Y:"Yankee",Z:"Zulu",0:"Zero",1:"One",2:"Two",3:"Three",4:"Four",5:"Five",6:"Six",7:"Seven",8:"Eight",9:"Niner"};


function strToNato(str){
    return str.toUpperCase().split('').map(l => MAP[l] || l).join(' ');
}

console.log(strToNato('ABC123'));

Answer 3

Answer №2

Make sure to pass in the character at the specified position, not the value of the loop index:

result += charAtPosition( str.charAt( i ) )

Furthermore, it seems like your loop is exceeding the string's length. You should replace <= with <

for (var i = 0; i < str.length; i++) {

There may be other issues with your program, but this addresses the specific query at hand.

Answer 4

Make sure to pass in the character at the specified position, not the value of the loop index:

result += charAtPosition( str.charAt( i ) )

Furthermore, it seems like your loop is exceeding the string's length. You should replace <= with <

for (var i = 0; i < str.length; i++) {

There may be other issues with your program, but this addresses the specific query at hand.

Answer 5

Answer №3

There are a few modifications needed:

In response to your query, the call to ltrToNato is receiving an integer - the value of i. Instead of using the index directly, you should fetch the character at that index and then append the return value from ltrToNato to the accumulator variable s (you can simplify this concatenation using the += operator):

s += ltrToNato(str[i]);

You could also utilize charAt() instead of treating the string as an array for indexing.
The for loop shouldn't iterate until the full length because i starts at 0. You can either adjust the middle expression to stop at one less than the total length with i <= str.length-1, or use a less than comparison: i < str.length.

Instead of employing a traditional for loop, you can leverage Array.prototype.reduce on the input string str:
```
return Array.prototype.reduce.call(str,function(returnVal,character) {
  return returnVal + ltrToNato(character);
});
```
This approach eliminates the need to manage the for loop manually. Further insights into functional programming can be found here.
At the end of wordToNato1, ensure to return the concatenated string stored in the variable s:

return s;
The evaluation of x.match() will yield an array or null. Consequently, if your conditional statement else if (x = x.match(/[0-9]/g)) executes, it will inadvertently assign the output of the match() function to x, overwriting its initial value. This modified value may then be used in the final else block (i.e., return x).

Check out these adjustments reflected in the code snippet below:

var ltrToNato = function(ch) {
  var x = ch
  var nato =
    ('{"A": "Alpha", "B": "Bravo", "C": "Charlie", "D": "Delta", "E": "Echo", "F": "Foxtrot", "G": "Golf", "H": "Hotel", "I": "India", "J": "Juliet", "K": "Kilo",\
  "L": "Lima", "M": "Mike", "N": "November", "O": "Oscar", "P": "Papa", "Q": "Quebec", "R": "Romeo", "S": "Sierra", "T": "Tango", "U": "Uniform", "V": "Victor",\
  "W": "Whiskey", "X": "X-Ray", "Y": "Yankee", "Z": "Zulu", "0" : "Zero", "1" : "One", "2" : "Two", "3" : "Three", "4" : "Four", "5" : "Five", "6" : "Six",\
   "7" : "Seven", "8" : "Eight", "9" : "Niner"}')
  var natoLower = nato.toLowerCase()
  var natoAlpha = JSON.parse(nato)
  var natoAlphaLower = JSON.parse(natoLower)
  if (ch >= "A" && ch <= "Z")
    return natoAlpha[ch]
  else if (ch >= "a" && ch <= "z")
    return (natoAlphaLower[ch])
  else if (x.match(/[0-9]/g))
    return natoAlpha[ch]
  else
    return x
}

//B
var wordToNato1 = function(str) {
  var s = ""
  for (var i = 0; i <= str.length-1; i++) {
    s += ltrToNato(str[i])
  }
  return s;
}
console.log('nato: '+wordToNato1("ABC123"));

Answer 6

There are a few modifications needed:

In response to your query, the call to ltrToNato is receiving an integer - the value of i. Instead of using the index directly, you should fetch the character at that index and then append the return value from ltrToNato to the accumulator variable s (you can simplify this concatenation using the += operator):

s += ltrToNato(str[i]);

You could also utilize charAt() instead of treating the string as an array for indexing.
The for loop shouldn't iterate until the full length because i starts at 0. You can either adjust the middle expression to stop at one less than the total length with i <= str.length-1, or use a less than comparison: i < str.length.

Instead of employing a traditional for loop, you can leverage Array.prototype.reduce on the input string str:
```
return Array.prototype.reduce.call(str,function(returnVal,character) {
  return returnVal + ltrToNato(character);
});
```
This approach eliminates the need to manage the for loop manually. Further insights into functional programming can be found here.
At the end of wordToNato1, ensure to return the concatenated string stored in the variable s:

return s;
The evaluation of x.match() will yield an array or null. Consequently, if your conditional statement else if (x = x.match(/[0-9]/g)) executes, it will inadvertently assign the output of the match() function to x, overwriting its initial value. This modified value may then be used in the final else block (i.e., return x).

Check out these adjustments reflected in the code snippet below:

var ltrToNato = function(ch) {
  var x = ch
  var nato =
    ('{"A": "Alpha", "B": "Bravo", "C": "Charlie", "D": "Delta", "E": "Echo", "F": "Foxtrot", "G": "Golf", "H": "Hotel", "I": "India", "J": "Juliet", "K": "Kilo",\
  "L": "Lima", "M": "Mike", "N": "November", "O": "Oscar", "P": "Papa", "Q": "Quebec", "R": "Romeo", "S": "Sierra", "T": "Tango", "U": "Uniform", "V": "Victor",\
  "W": "Whiskey", "X": "X-Ray", "Y": "Yankee", "Z": "Zulu", "0" : "Zero", "1" : "One", "2" : "Two", "3" : "Three", "4" : "Four", "5" : "Five", "6" : "Six",\
   "7" : "Seven", "8" : "Eight", "9" : "Niner"}')
  var natoLower = nato.toLowerCase()
  var natoAlpha = JSON.parse(nato)
  var natoAlphaLower = JSON.parse(natoLower)
  if (ch >= "A" && ch <= "Z")
    return natoAlpha[ch]
  else if (ch >= "a" && ch <= "z")
    return (natoAlphaLower[ch])
  else if (x.match(/[0-9]/g))
    return natoAlpha[ch]
  else
    return x
}

//B
var wordToNato1 = function(str) {
  var s = ""
  for (var i = 0; i <= str.length-1; i++) {
    s += ltrToNato(str[i])
  }
  return s;
}
console.log('nato: '+wordToNato1("ABC123"));

The error message "ch.match is not a function" appeared in the Javascript code

Answer №1

Answer №2

Answer №3

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