The concept of reducing functions in JavaScript and the significance of extra brackets

My function looks like this:

function ross(array) {
  return array.map(function(data) {
   return data.reduce(function(obj, item) {
      obj[item[0]] = item[1];
      return obj;
    }, {});
  });
}
ross(array);

This code is responsible for converting a 3-dimensional array into an array of objects. The part I am particularly interested in is as follows:

return data.reduce(function(obj, item) {
      obj[item[0]] = item[1];
      return obj;
    }, {});

In the return obj line, there is another set of brackets after the comma (,). I have tried changing it to square brackets [], which resulted in the output being transformed into a two-dimensional array.

I am curious if anyone can clarify what purpose the extra bracket serves?

Answer №1

These curly braces represent an empty object. The second parameter in the reduce function serves as an initial value for the accumulator passed to the callback function. Therefore, these curly braces specify what the callback function perceives as obj during the first call and all subsequent calls.

Essentially, this code is equivalent to:

var obj = {};
data.forEach(function(item) {
  obj[item[0]] = item[1];
});
return obj;

reduce is being utilized (some might argue overutilized, since the accumulator remains unchanged; however, it's a common practice) to condense three statements into one outer statement.

Answer №2

According to W3Schools: "The setTimeout() method calls a function or evaluates an expression after a specified number of milliseconds."

The second argument represents the delay in milliseconds before executing the function, which is provided as the parameter callback. If you omit this argument, the default delay is set to 0.

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