The Ajax POST call was unsuccessful

Question

The Ajax POST call was unsuccessful

I seem to be encountering an issue, even though everything appears to be correct. I am currently developing on localhost and I am facing difficulties loading a file.

This is the code I am using. I am working in NetBeans and the console shows no errors.

<!DOCTYPE html>
<html>
<head>
<script>
function loadXMLDoc() {
    var xmlhttp;
    if (window.XMLHttpRequest) { // code for IE7+, Firefox, Chrome, Opera, Safari
        xmlhttp = new XMLHttpRequest();
    } else { // code for IE6, IE5
        xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
    }
    xmlhttp.onreadystatechange = function () {
        if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
            document.getElementById("myDiv").innerHTML = xmlhttp.responseText;
        }
    }
    xmlhttp.open("POST", "demo_post.php", true);
    xmlhttp.send();
}
</script>
</head>
<body>

<h2>AJAX</h2>
<button type="button" onclick="loadXMLDoc()">Request data</button>
<div id="myDiv"></div>

</body>
</html>

Even after running this code snippet, there are no visible results.

javascript ajax

Answer 1

Answer №1

Make sure to specify your request header between the .open() and .send() calls, like this:

xmlhttp.open("POST", "demo_post.php", true);
xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");
xmlhttp.send();

This is the manual way of doing it without relying on jQuery.

Answer 2

Make sure to specify your request header between the .open() and .send() calls, like this:

xmlhttp.open("POST", "demo_post.php", true);
xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");
xmlhttp.send();

This is the manual way of doing it without relying on jQuery.

Answer 3

Answer №2

One helpful suggestion is to check the error console in your browser instead of using Netbeans. It's also important to learn how to set breakpoints in JavaScript.

Here's an example demonstrating what you're trying to accomplish with jQuery, which is easier than using plain JavaScript:

<!DOCTYPE html>
<html>
<head>
<script type="text/javascript" src="http://code.jquery.com/jquery-2.0.3.min.js"></script>
<script type="text/javascript">

   // Using jQuery selectors and functions for more efficient code
   $(".loadData").click(function (event) {

       $.ajax({
          url: 'demo_post.php',
          type: 'POST',
          dataType: 'html',
          cache: false,
          data: 'foo=bar',
          error: function (error_response) {
             $("#myDiv").empty().append(error_response.status);

          },
          success: function (response) {
             $("#myDiv").empty().append(response);

          }
       });

   });

</script>
</head>
<body>
<h2>AJAX</h2>
<button type="button" class="loadData">Request data</button>
<div id="myDiv"></div>

</body>
</html>

For more information on jQuery, visit http://api.jquery.com. You can also explore jQuery's AJAX functions at http://api.jquery.com/jQuery.ajax/

Answer 4

One helpful suggestion is to check the error console in your browser instead of using Netbeans. It's also important to learn how to set breakpoints in JavaScript.

Here's an example demonstrating what you're trying to accomplish with jQuery, which is easier than using plain JavaScript:

<!DOCTYPE html>
<html>
<head>
<script type="text/javascript" src="http://code.jquery.com/jquery-2.0.3.min.js"></script>
<script type="text/javascript">

   // Using jQuery selectors and functions for more efficient code
   $(".loadData").click(function (event) {

       $.ajax({
          url: 'demo_post.php',
          type: 'POST',
          dataType: 'html',
          cache: false,
          data: 'foo=bar',
          error: function (error_response) {
             $("#myDiv").empty().append(error_response.status);

          },
          success: function (response) {
             $("#myDiv").empty().append(response);

          }
       });

   });

</script>
</head>
<body>
<h2>AJAX</h2>
<button type="button" class="loadData">Request data</button>
<div id="myDiv"></div>

</body>
</html>

For more information on jQuery, visit http://api.jquery.com. You can also explore jQuery's AJAX functions at http://api.jquery.com/jQuery.ajax/

Answer 5

Answer №3

It appears that the code provided is specifically tailored for handling GET requests. In this scenario, there is no need to implement POST over GET, especially since no parameters are being passed and it is not a form submission. This aligns with the sentiments expressed by @Jackson as well.

  <!DOCTYPE html>
  <html>
  <head>
  <!--While online JS files can be utilized, I have downloaded the necessary js file from code.jquery.com/jquery-2.0.3.min.js and stored it in the same local directory-->
  <script type="text/javascript" src="/jquery-2.0.3.min.js"></script>
  <script type="text/javascript">
  function loadXMLDoc()
  {
  var xmlhttp;
  if (window.XMLHttpRequest)
  {// Supports IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
  else
  {// For IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
  xmlhttp.onreadystatechange=function()
  {
 if (xmlhttp.readyState==4 && xmlhttp.status==200)
  {
  document.getElementById("myDiv").innerHTML=xmlhttp.responseText;
  }
 }
 xmlhttp.open("GET","demo_post.php",true);
 xmlhttp.send();
 }
 </script>
 </head>
 <body>
 <h2>AJAX</h2>
 <button type="button" onclick="loadXMLDoc()">Request data</button>
 <div id="myDiv"></div>

 </body>
 </html>

Answer 6

It appears that the code provided is specifically tailored for handling GET requests. In this scenario, there is no need to implement POST over GET, especially since no parameters are being passed and it is not a form submission. This aligns with the sentiments expressed by @Jackson as well.

  <!DOCTYPE html>
  <html>
  <head>
  <!--While online JS files can be utilized, I have downloaded the necessary js file from code.jquery.com/jquery-2.0.3.min.js and stored it in the same local directory-->
  <script type="text/javascript" src="/jquery-2.0.3.min.js"></script>
  <script type="text/javascript">
  function loadXMLDoc()
  {
  var xmlhttp;
  if (window.XMLHttpRequest)
  {// Supports IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
  else
  {// For IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
  xmlhttp.onreadystatechange=function()
  {
 if (xmlhttp.readyState==4 && xmlhttp.status==200)
  {
  document.getElementById("myDiv").innerHTML=xmlhttp.responseText;
  }
 }
 xmlhttp.open("GET","demo_post.php",true);
 xmlhttp.send();
 }
 </script>
 </head>
 <body>
 <h2>AJAX</h2>
 <button type="button" onclick="loadXMLDoc()">Request data</button>
 <div id="myDiv"></div>

 </body>
 </html>

The Ajax POST call was unsuccessful

Answer №1

Answer №2

Answer №3

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