Check out the code snippet below:
MyObject.prototype.doIt = function()
{
let a = this.obj1;
let b = this.obj2;
}
I need to find a way to switch the values of this.obj1 and this.obj2, making obj1 take on the value of obj2 and vice versa.
Please be aware that I'm dealing with non-primitive types here.
By utilizing a basic identity function, you have the ability to switch any number of objects or literals regardless of their types:
var swap = function (x){return x};
b = swap(a, a=b);
c = swap(a, a=b, b=c);
This technique is effective in JavaScript due to its flexibility in accepting extra arguments, even if they are not specifically declared or utilized. The a=b assignments take place after passing a into the function.
An example of destructuring objects is shown in the code snippet below:
let num1 = 10;
let num2 = 20;
[num1, num2] = [num2, num1];
To perform a swap between two objects, it is recommended to use a temporary variable to hold the contents of one object before swapping them:
var temporaryObject = this.firstObject;
this.firstObject = this.secondObject;
this.secondObject = temporaryObject;
To easily swap the properties, you can use the following code:
MyObject.prototype.doIt = function()
{
var a = this.obj1;
this.obj1 = this.obj2;
this.obj2 = a;
}
Even though obj1 and obj2 are not primitive types, their type does not matter in this swapping process.
If there are existing references to this.obj1 or this.obj2 outside of this code, those references will not be swapped.
Completely swapping this.obj1 and this.obj2, including existing references, is not possible. You could remove all properties from one object, move them to the other object, and vice versa, but you cannot alter the prototypes of objects to fundamentally swap their identities.
Imagine you have two concrete objects, let's call them object1 and object2.
If you want to exchange their positions,
You can follow these steps:
var temporary1 = object1;
var temporary2 = object2;
object1 = temporary2;
object2 = temporary1;
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