Successful Ajax response notification

Question

Successful Ajax response notification

I am new to using ajax and I want to implement a .post method with an if condition to notify the user of its success or failure.

Here is my code for .post:

$.post("ajaxRegistering.php",{
                  name: name,
                  lastname: lastname,
                  secondlastname: secondlastname,
                  usernameone: usernameone,
                  email: email,
                  passwordone: passwordone,
                  studentnumberone: studentnumberone,
                  temp: temp
            },
                function(data, status){
                  // alert("Data: " + name + "\nStatus: " + status) ;
                  sweetAlert("Success", "your account has been created.", "success") ;

            }) ;

The above ajax code works fine but I am struggling with adding a failure case. Here is what I have tried:

$.ajax ({
            type: "POST",
            url: "website.php",
            data: data,
            success: function(dataone){
              sweetAlert("Success", "you have successfully enrolled in momentoSagrado.", "success") ;
            } 

          }) ;

Can someone assist me with this? I believe it may be a simple mistake that I am making.

javascript ajax post

Answer 1

Answer №1

Make sure to assign error to a function within your $.ajax() declaration.

$.ajax({
    type: "POST",
    url: "website.php",
    data: data,
    success: function(dataOne) {
        sweetAlert("Success","You have successfully rolled in momentoSagrado.","success");
    },
    error: function(xhr, status, errorThrown) {
        // handle any errors here
    }
});

Answer 2

Make sure to assign error to a function within your $.ajax() declaration.

$.ajax({
    type: "POST",
    url: "website.php",
    data: data,
    success: function(dataOne) {
        sweetAlert("Success","You have successfully rolled in momentoSagrado.","success");
    },
    error: function(xhr, status, errorThrown) {
        // handle any errors here
    }
});

Answer 3

Answer №2

According to the jQuery Docs, using .post() is essentially a shorthand for:

$.ajax({
  type: "POST",
  url: url,
  data: data,
  success: success,
  dataType: dataType
});

To implement a success function, you can do it like this:

$.post( "website.php", function( data ) {
    sweetAlert("Successfully", "created your account.", "success") ;
});

If you encounter an error while using .post(), you will need to chain the fail function as mentioned in the documentation:

// Assign handlers immediately after making the request,
// and remember the jqxhr object for this request
var jqxhr = $.post( "example.php", function() {
  alert( "success" );
})
  .done(function() {
    alert( "second success" );
  })
  .fail(function() {
    alert( "error" );
  })
  .always(function() {
    alert( "finished" );
});

Answer 4

According to the jQuery Docs, using .post() is essentially a shorthand for:

$.ajax({
  type: "POST",
  url: url,
  data: data,
  success: success,
  dataType: dataType
});

To implement a success function, you can do it like this:

$.post( "website.php", function( data ) {
    sweetAlert("Successfully", "created your account.", "success") ;
});

If you encounter an error while using .post(), you will need to chain the fail function as mentioned in the documentation:

// Assign handlers immediately after making the request,
// and remember the jqxhr object for this request
var jqxhr = $.post( "example.php", function() {
  alert( "success" );
})
  .done(function() {
    alert( "second success" );
  })
  .fail(function() {
    alert( "error" );
  })
  .always(function() {
    alert( "finished" );
});

Successful Ajax response notification

Answer №1

Answer №2

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