Create a custom function findMax that takes in a parameter named numbers, which is an array of numerical values. Inside the function, locate the highest number in the array and then return this value.
// Helpful tip: Ensure that the max function consistently returns an element within the array rather than just any number.
https://i.sstatic.net/WWmh4.jpg
An error message is being displayed:
Your output was '4'. This is not accurate as the maximum number should be 5.
Based on the problem specifications, the code displayed in your screenshot appears to be contradictory as it returns an index instead of the requested element. To find the maximum element in a given array, you can utilize the following concise one-liner:
function getMaximumElement(numbers){
return numbers.reduce((currentMax, num) => num > currentMax ? num : currentMax);
}
If you require the index of the maximum element, you can employ the previously defined function as follows:
function getIndexOfMaxElement(numbers){
return numbers.indexOf(getMaximumElement(numbers));
}
An effective technique is to continuously update the maximum number in the array whenever the for Loop detects a larger number, like this:
num = [8, 12, 6, 21, 33, 15, 100];
findMax(num);
function findMax(numbers) {
maxNumber = numbers[0];
for (j = 0; j < numbers.length; j++) {
if (numbers[j] > maxNumber) {
maxNumber = numbers[j];
}
}
return maxNumber;
}
Executing this code will output 100 which should work quite well :)
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