I am working with an array that contains mathematical signs.
var signs = ['+', '-', '*', '/'];
In addition, I have two variables representing digits to combine with each sign from the array.
var right_digit = 1;
var left_digit = 5;
I am curious if it is possible to perform the following operation in JavaScript:
var answer = left_digit + sign[0] + right_digit;
To steer clear of using eval, consider implementing a method similar to this:
var operators = {
'+': function(operand1, operand2) { return operand1 + operand2; },
...
};
var calculatedAnswer = operators['+'](first_num, second_num);
It seems unlikely that you can directly accomplish this task, but you could create a function to handle it.
function performOperation(x, y, z) {
switch (z) {
case "+":
return x + y;
case "-":
return x - y;
case "*":
return x * y;
default:
return x / y;
}
}
If you need to dynamically evaluate operators, you can accomplish this using eval:
var result = eval(second_num + operation[0] + first_num);
However, keep in mind that using `eval` is not recommended due to potential security vulnerabilities (especially with untrusted data) and performance issues as the code needs to be analyzed each time it's executed.
Alternatively, a better approach would be to use a switch statement like the following:
function calculate(x, operator, y) {
switch (operator) {
case "+":
return x + y;
case "-":
return x - y;
case "*":
return x * y;
case "/":
return x / y;
}
}
var result = calculate(second_num, operation[0], first_num);
One approach is to utilize the eval function:
var result = eval(first_number + operator[0] + second_number);
An effective method using eval (it removes digits and symbols, throwing an error for incorrect format):
function performCalculation(expression) {
var matches = /^(\d+)([+\-*/])(\d+)$/.exec(expression);
if(!matches) {
throw "Invalid expression";
}
return eval(matches[1] + matches[2] + matches[3]);
}
performCalculation('2*4'); // 8
This allows you to execute:
performCalculation(left + operation + right);
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