Steps to transform every character into binary code

Question

Steps to transform every character into binary code

I am facing an issue where I need to convert each character into a binary number based on a specific condition. Numbers greater than or equal to 5 should be converted to 1, while numbers less than or equal to 4 should be converted to 0.

Here is the entire code snippet:

n = [
  '0110100000', '1001011111',
  '1110001010', '0111010101',
  '0011100110', '1010011001',
  '1101100100', '1011010100',
  '1001100111', '1000011000'
] // array of binary 

let bin = [] // converting to numbers
length = n.length;
for (var i = 0; i < length; i++)
  bin.push(parseInt(n[i]));

var sum = 0; // sum of all binaries
for (var i = 0; i < bin.length; i++) {
  sum += bin[i];
}
console.log(sum); // 7466454644

// ...
// code converting each character
// ...

// console.log(sumConverted) // 1011010100

Is there a way for me to convert characters greater than or equal to 5 to 1 and those less than 5 to 0?

For example:

7466454644
7=1, 4=0, 6=1, 6=1, 4=0, 5=1, 4=0, 6=1, 4=0, 4=0
return 1011010100

javascript arrays binary numbers converters

Answer 1

Answer №1

In each iteration, the concept is to extract the last digit from the whole number using last_digit = number%10, then eliminate this last digit from the original number by performing number = Math.ceil(number/10). Repeat this process until the number reaches 0

For instance:

number = 123;
last_digit = 123%10 = 3
number = Math.ceil(number/10) = 12

let num = 7466454644;

let convertedBinary = '';
while (num) {
  const binary = (num % 10) < 5 ? 0 : 1;
  convertedBinary = `${binary}${convertedBinary}`;
  num = Math.floor(num/10);
}

console.log(convertedBinary);

May this explanation be of assistance!

Answer 2

In each iteration, the concept is to extract the last digit from the whole number using last_digit = number%10, then eliminate this last digit from the original number by performing number = Math.ceil(number/10). Repeat this process until the number reaches 0

For instance:

number = 123;
last_digit = 123%10 = 3
number = Math.ceil(number/10) = 12

let num = 7466454644;

let convertedBinary = '';
while (num) {
  const binary = (num % 10) < 5 ? 0 : 1;
  convertedBinary = `${binary}${convertedBinary}`;
  num = Math.floor(num/10);
}

console.log(convertedBinary);

May this explanation be of assistance!

Answer 3

Answer №2

Break down the number into individual digits using a string and iterate over them:

const sum = 628490795;

const digitsString = sum.toString(); // convert to string

const modifiedDigits = digitsString
    .split("")                 // separate each digit
    .map((digit) => +(+digit > 7))     // if a digit is greater than 7, turn it into 1
    .join("");                 // merge back into a string
    
console.log(modifiedDigits);           // 001100110

+(+digit > 7) may seem cryptic, but it is simply equal to Number(Number(digit) > 7). The aim is to transform a boolean value into either 0 or 1 by changing its type.

Answer 4

Break down the number into individual digits using a string and iterate over them:

const sum = 628490795;

const digitsString = sum.toString(); // convert to string

const modifiedDigits = digitsString
    .split("")                 // separate each digit
    .map((digit) => +(+digit > 7))     // if a digit is greater than 7, turn it into 1
    .join("");                 // merge back into a string
    
console.log(modifiedDigits);           // 001100110

+(+digit > 7) may seem cryptic, but it is simply equal to Number(Number(digit) > 7). The aim is to transform a boolean value into either 0 or 1 by changing its type.

Steps to transform every character into binary code

Answer №1

Answer №2

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