Steps to replicate the items in an array

Question

Steps to replicate the items in an array

Suppose we have an array :

var array_1 = ['c','b','a'];

What would be the most efficient method to convert array_1 into

['c','c','b','b','a','a'];

or possibly

['c','c','c','b','b','b','a','a','a'];

javascript arrays

Answer 1

Answer №1

One approach is to utilize flatMap along with fill in the following way:

function replicate(arr, count) {
  return arr.flatMap(num => Array(count).fill(num))
}

console.log(JSON.stringify(replicate([1,2,3], 2)))
console.log(JSON.stringify(replicate([1,2,3], 3)))

Answer 2

One approach is to utilize flatMap along with fill in the following way:

function replicate(arr, count) {
  return arr.flatMap(num => Array(count).fill(num))
}

console.log(JSON.stringify(replicate([1,2,3], 2)))
console.log(JSON.stringify(replicate([1,2,3], 3)))

Answer 3

Answer №2

Utilizing the brand new .flat() method allows you to condense an array into a single dimension and multiply the elements by mapping each element to an array containing those elements individually.

var arr1 = ['c', 'b', 'a'];

var arr2 = arr1.map(e => ([e, e, e])).flat();

console.log(arr2);

Answer 4

Utilizing the brand new .flat() method allows you to condense an array into a single dimension and multiply the elements by mapping each element to an array containing those elements individually.

var arr1 = ['c', 'b', 'a'];

var arr2 = arr1.map(e => ([e, e, e])).flat();

console.log(arr2);

Answer 5

Answer №3

When iterating over an array and performing additive operations, the choice of method often boils down to personal style. One common approach is using the Array.reduce method...

const arr1 = ['x', 'y', 'z']
const arr2 = arr1.reduce((accumulator, currentValue) => [...accumulator, currentValue, currentValue, currentValue], [])

Alternative methods like map or forEach could also achieve similar results.

Answer 6

When iterating over an array and performing additive operations, the choice of method often boils down to personal style. One common approach is using the Array.reduce method...

const arr1 = ['x', 'y', 'z']
const arr2 = arr1.reduce((accumulator, currentValue) => [...accumulator, currentValue, currentValue, currentValue], [])

Alternative methods like map or forEach could also achieve similar results.

Answer 7

Answer №4

To duplicate a character in an array, loop through the initial array and use the Array(x).fill(c) method for each character. Here, x represents the number of duplicates and c is the character you want to replicate. Finally, combine all the new arrays into one unified array.

Answer 8

To duplicate a character in an array, loop through the initial array and use the Array(x).fill(c) method for each character. Here, x represents the number of duplicates and c is the character you want to replicate. Finally, combine all the new arrays into one unified array.

Answer 9

Answer №5

Utilizing a basic forEach and for loop.

To create multiple duplicates of your array, you can use a function that takes in your array and the desired number of duplications.

const myArray = ['c', 'b', 'a'];

const resultArr1 = makeDuplicates(myArray, 2);
console.log(resultArr1);

const resultArr2 = makeDuplicates(myArray, 3);
console.log(resultArr2);

function makeDuplicates(arr, times) {
  let duplicatedArray = [];
  arr.forEach(item => {
    for(i=0; i < times; i++) {
      duplicatedArray.push(item);
    }
  });
  return duplicatedArray;
}

Answer 10

Utilizing a basic forEach and for loop.

To create multiple duplicates of your array, you can use a function that takes in your array and the desired number of duplications.

const myArray = ['c', 'b', 'a'];

const resultArr1 = makeDuplicates(myArray, 2);
console.log(resultArr1);

const resultArr2 = makeDuplicates(myArray, 3);
console.log(resultArr2);

function makeDuplicates(arr, times) {
  let duplicatedArray = [];
  arr.forEach(item => {
    for(i=0; i < times; i++) {
      duplicatedArray.push(item);
    }
  });
  return duplicatedArray;
}

Answer 11

Answer №6

public static char[] replicateArray(char arr[], int numberOfCopies) {
    char newArr[] = new char[((arr.length) * numberOfCopies)];
    char temp;

    int p = 0;
    for (int k = 0; k < arr.length; k++) {
        for (int i = p; i < newArr.length; i++) {

            for (int j = 0; j < numberOfCopies; j++) {
                newArr[i + j] = arr[k];

            }
            p = i + numberOfCopies;
            break;

        }
    }
    return newArr;

    }

Answer 12

public static char[] replicateArray(char arr[], int numberOfCopies) {
    char newArr[] = new char[((arr.length) * numberOfCopies)];
    char temp;

    int p = 0;
    for (int k = 0; k < arr.length; k++) {
        for (int i = p; i < newArr.length; i++) {

            for (int j = 0; j < numberOfCopies; j++) {
                newArr[i + j] = arr[k];

            }
            p = i + numberOfCopies;
            break;

        }
    }
    return newArr;

    }

Answer 13

Answer №7

let sampleArray = ['a','b','c'];   
/* If the array contains numbers, you can change elements and handle duplicacy like this - sampleArray = [1,2,3] */

getModifiedResult = (inputArray, duplicacyNumber) => {
    return  duplicacyNumber <= 0 ? inputArray : inputArray.reduce((current, accumulator) =>{
        let arr1 = Array(duplicacyNumber).fill(current);
        let arr2 = Array(duplicacyNumber).fill(accumulator);

        arr1 = isNaN(current) ? arr1   : arr1.map(Number);
        arr2 = isNaN(accumulator) ?  arr2 : arr2.map(Number);

        return (Array.isArray(current) ? current : arr1 ).concat(arr2)
    })
}

console.log( getModifiedResult(sampleArray, 5) )

Answer 14

let sampleArray = ['a','b','c'];   
/* If the array contains numbers, you can change elements and handle duplicacy like this - sampleArray = [1,2,3] */

getModifiedResult = (inputArray, duplicacyNumber) => {
    return  duplicacyNumber <= 0 ? inputArray : inputArray.reduce((current, accumulator) =>{
        let arr1 = Array(duplicacyNumber).fill(current);
        let arr2 = Array(duplicacyNumber).fill(accumulator);

        arr1 = isNaN(current) ? arr1   : arr1.map(Number);
        arr2 = isNaN(accumulator) ?  arr2 : arr2.map(Number);

        return (Array.isArray(current) ? current : arr1 ).concat(arr2)
    })
}

console.log( getModifiedResult(sampleArray, 5) )

Steps to replicate the items in an array

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

Answer №7

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