Steps for attaching distinct event listeners to individual elements:

I am currently developing a laravel project and I am faced with the task of iterating over a resource using the @foreach blade directive like this:

@foreach($users as $user)
    <p @click="toggleClick">{{ $user->name }}</p>
    <p v-if="clicked">Lorem ipsum</p>
@endforeach

An issue has arisen with this method. The problem is that if there are five users, the toggleClick listener will be attached to every paragraph. Therefore, clicking on one user will cause all hidden Lorem Ipsum paragraphs to immediately display for all users. Here is an illustration:

John Doe

Lorem ipsum

Jane Doe (Clicked)

Lorem ipsum

Jimmy Doe

Lorem ipsum

What I desire instead is this:

John Doe

Jane Doe (Clicked)

Lorem ipsum

Jimmy Doe

How can I achieve this desired outcome?

Answer №1

To ensure that each paragraph functions separately, it is necessary to have individual listeners.
One approach is to include an index in your loop and call toggleClick(event, i) where i represents the paragraph number.
In your HTML, display visible paragraphs based on a Boolean field.

Answer №2

To make it more structured, enclose it in a div or something similar.

@foreach($users as $user)
    <div>
        <p @click="toggleClick">{{ $user->name }}</p>
        <p v-if="clicked">Lorem ipsum</p>
    <div>
@endforeach

Use JavaScript in jQuery

q = f() ->
    $(this).parent().find('[v-if="clicked"]')
    // ...

Answer №3

For those open to utilizing classes and Javascript, I propose the following method:

var names = document.getElementsByClassName("toggleClick");

for (var i = 0; i < names.length; i++) {
  names[i].addEventListener("click", function(index, value) {
    this.nextElementSibling.classList.toggle("hiddenText");
  })
}
.hiddenText {
  display: none;
}
<p class="toggleClick">John Doe</p>
<p class="hiddenText">Lorem ipsum 1</p>
<p class="toggleClick">Jane Doe</p>
<p class="hiddenText">Lorem ipsum 2</p>
<p class="toggleClick">Jimmy Doe</p>
<p class="hiddenText">Lorem ipsum 3</p>

I trust this solution proves useful.

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