Sorting Object Values with Alternate Order

Question

Sorting Object Values with Alternate Order

Is there a way to sort a JSON response object array in a specific order, especially when dealing with non-English characters like Umlauts?

object {
  item: 1,
  users: [
   {name: "A", age: "23"}, 
   {name: "B", age: "24"},
   {name: "Ä", age: "27"}
 ]
}

Expected name sorting would be A, Ä, and B.

Upon attempting to use localeCompare() for sorting:

object.sort(function (a, b) { return a.localeCompare(b); });

An error is encountered stating that object.sort is not a function. Is there an alternate method to sort the object array?

javascript angularjs

Answer 1

Answer №1

In order to sort the object, you must utilize its properties.

var object = { item: 1, users: [{ name: "A", age: "23" }, { name: "B", age: "24" }, { name: "Ä", age: "27" }] };

object.users.sort(function (a, b) { return a.name.localeCompare(b.name); });

console.log(object);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

In order to sort the object, you must utilize its properties.

var object = { item: 1, users: [{ name: "A", age: "23" }, { name: "B", age: "24" }, { name: "Ä", age: "27" }] };

object.users.sort(function (a, b) { return a.name.localeCompare(b.name); });

console.log(object);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 3

Answer №2

Remember to always apply the sort() function to the array itself, not the surrounding object. Objects do not possess this method and key order is not guaranteed in general. It's best practice to use arrays for "ordered" data rather than objects!

In this instance, we are utilizing the o.users array. The resulting output n is also an array.

IMPORTANT: Avoid using reserved keywords as variable names. If you choose to use object as a variable name, it's highly advised not to do so! I've opted for o instead. While object isn't a reserved keyword, Object (with a capital O) is. These two can easily be mistaken for one another.

var o = {
  "item": 1,
  "users": [
    { "name": "A", "age": "23" },
    { "name": "B", "age": "24" },
    { "name": "Ä", "age": "27" }
  ]
};

var n = o.users.sort((a, b) => a.name.localeCompare(b.name, "de"));

console.log(n);

Answer 4

Remember to always apply the sort() function to the array itself, not the surrounding object. Objects do not possess this method and key order is not guaranteed in general. It's best practice to use arrays for "ordered" data rather than objects!

In this instance, we are utilizing the o.users array. The resulting output n is also an array.

IMPORTANT: Avoid using reserved keywords as variable names. If you choose to use object as a variable name, it's highly advised not to do so! I've opted for o instead. While object isn't a reserved keyword, Object (with a capital O) is. These two can easily be mistaken for one another.

var o = {
  "item": 1,
  "users": [
    { "name": "A", "age": "23" },
    { "name": "B", "age": "24" },
    { "name": "Ä", "age": "27" }
  ]
};

var n = o.users.sort((a, b) => a.name.localeCompare(b.name, "de"));

console.log(n);

Sorting Object Values with Alternate Order

Answer №1

Answer №2

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