Set the RegEx so that the entire match is non-capturing

Recently, I've been working with a regex pattern that looks like this:

const newRegex = /(\d{4})-(\d{2})-(\d{2}) (\d{2}):(\d{2}):(\d{2})/;

const finalResult = "1988-02-01 12:12:12".match(newRegex);

console.log(finalResult)

I noticed that the first item in the result matches the whole expression. Is there any way to exclude this whole match from the result? Currently, I have been using shift() on the result array, but I'm curious if there's a way to mark the whole match as non-capturing in some way.

Answer №1

To extract the first value from an array result using destructuring, you can use [,...result]:

const regex = /(\d{4})-(\d{2})-(\d{2}) (\d{2}):(\d{2}):(\d{2})/;

const [,...result] = "1988-02-01 12:12:12".match(regex);

console.log(result)

If you are confident in the input format, a simpler approach is:

result = "1988-02-01 12:12:12".match(/\d+/g)

const regex = /(\d{4})-(\d{2})-(\d{2}) (\d{2}):(\d{2}):(\d{2})/;

const result = "1988-02-01 12:12:12".match(/\d+/g);

console.log(result)

You can add more validation with .match(/(^\d{4}|\b\d{2})\b/g)

const regex = /(\d{4})-(\d{2})-(\d{2}) (\d{2}):(\d{2}):(\d{2})/;

const result = "1988-02-01 12:12:12".match(/(^\d{4}|\b\d{2})\b/g);

console.log(result)

If you need numeric equivalents in the array, use Number as a callback function with map:

const regex = /(\d{4})-(\d{2})-(\d{2}) (\d{2}):(\d{2}):(\d{2})/;

const [,...result] = ("1988-02-01 12:12:12".match(regex)||[]).map(Number);

console.log(result)

The use of ||[] ensures handling cases where no match is found by replacing null with an empty array.

Answer №2

If you're interested, check out this article on named groups

const regex = /((?<year>\d{4})-(?<month>\d{2})-(?<day>\d{2})) (?<hour>\d{2}):(?<minutes>\d{2}):(?<seconds>\d{2})/;

const result = "1988-02-01 12:12:12".match(regex).groups;

console.log(result)

console.log(Object.values(result))

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