Selenium web driver showcases its capability by successfully launching the Firefox browser, yet encounters an issue with an invalid address

     WebElement searchElement = driver.findElement(By.name("q"));
       
searchElement.sendKeys("Selenium WebDriver");
       
searchElement.submit();

Displays "Search Results"

public static void main(String[] args) {
        // TODO Auto-generated method stub

        driver.navigate().to("https://www.seleniumhq.org");

Answer №1

Substitute ,

driver.navigate().to("https://www.google.com");

using

driver.get("https://www.google.com");

Answer №2

Below is the solution to your inquiry:

In reference to your code snippet:

WebDriver driver = new FirefoxDriver();
driver.navigate().to("https://www.google.com");

It should have functioned correctly.

If you want to open a URL (assuming the URL is of type String), you can opt for one of the following alternative methods:

  1. Utilize the get() method to access the URL:

    WebDriver driver = new FirefoxDriver();
    driver.get("https://www.google.com");
    
  2. Employ the Navigation class to instantiate a new object and navigate to the URL:

    WebDriver driver = new FirefoxDriver();
    Navigation sara_navigate = driver.navigate();
    sara_navigate.to("https://www.google.com");
    

Kindly inform me if this satisfactorily addresses your query.

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