Screen out words from one string that appear in the other

Question

Screen out words from one string that appear in the other

Hello everyone, I am a beginner in JavaScript and I have a question about how to filter out two words from one string based on another string.

string1 = ['mango', 'iPhone', 'banana', 'computer', 'apple', 'keyboard', 'strawberry'];
string2 = ['mango', 'banana', 'apple', 'strawberry'];


const string3 = string1.filter(if (word) {})

This is what I have tried so far. I am unsure of what parameters to include in the filter() method. (1) I want to check if any word from string 1 matches with any word in string 2, (2) then exclude those words (3) and store the remaining ones in string 3.

If there are alternative methods to achieve the same result, I would greatly appreciate any suggestions.

javascript if-statement filter

Answer 1

Answer №1

To efficiently handle large array sizes, one effective method is to create a hash table (object) using the elements from the second string. Then, filter out the elements in the first string by checking their presence in the hash table.

Check out the code snippet below for an algorithm that operates with a time complexity of O(m+n), where m and n represent the lengths of the arrays:

const string1 = ['mango', 'iPhone', 'banana', 'computer', 'apple', 'keyboard', 'strawberry'];
const string2 = ['mango', 'banana', 'apple', 'strawberry'];

let obj = Object.fromEntries(string2.map(e => [e, true]));
let res = string1.filter(e => !obj[e]);
console.log(res);

Answer 2

To efficiently handle large array sizes, one effective method is to create a hash table (object) using the elements from the second string. Then, filter out the elements in the first string by checking their presence in the hash table.

Check out the code snippet below for an algorithm that operates with a time complexity of O(m+n), where m and n represent the lengths of the arrays:

const string1 = ['mango', 'iPhone', 'banana', 'computer', 'apple', 'keyboard', 'strawberry'];
const string2 = ['mango', 'banana', 'apple', 'strawberry'];

let obj = Object.fromEntries(string2.map(e => [e, true]));
let res = string1.filter(e => !obj[e]);
console.log(res);

Answer 3

Answer №2

To implement a filter, you can use the following code snippet

const filteredResult = stringData.filter(word => !forbiddenWords.includes(word));

If your goal is to eliminate items present in list2 and list3 from list1 simultaneously, you can follow this alternative solution

listOne = ['orange', 'tablet', 'pear', 'laptop', 'banana', 'mouse', 'grape'];
listTwo = ['orange', 'pear', 'banana', 'grape'];
listThree = ['4', '5', '6', 'tablet']

finalList = listOne.filter(word => !(listTwo.includes(word) || listThree.includes(word)));

console.log(finalList);   // ["laptop", "mouse"]

Answer 4

To implement a filter, you can use the following code snippet

const filteredResult = stringData.filter(word => !forbiddenWords.includes(word));

If your goal is to eliminate items present in list2 and list3 from list1 simultaneously, you can follow this alternative solution

listOne = ['orange', 'tablet', 'pear', 'laptop', 'banana', 'mouse', 'grape'];
listTwo = ['orange', 'pear', 'banana', 'grape'];
listThree = ['4', '5', '6', 'tablet']

finalList = listOne.filter(word => !(listTwo.includes(word) || listThree.includes(word)));

console.log(finalList);   // ["laptop", "mouse"]

Answer 5

Answer №3

Sort through array string1 to find elements that do not exist in array string2:

string3 = string1.filter(function(val) {
 return string2.indexOf(val) == -1;
});

Answer 6

Sort through array string1 to find elements that do not exist in array string2:

string3 = string1.filter(function(val) {
 return string2.indexOf(val) == -1;
});

Answer 7

Answer №4

Ensure that your variable names do not contain any spaces. When using the filter method, it requires a function as an argument and will return elements that evaluate to true when passed through that specified function.

list1 = ['carrot', 'TV', 'potato', 'laptop', 'orange', 'mouse', 'grape']
list2 = ['carrot', 'potato', 'orange', 'grape']

list3 = list1.filter(function(item) {
  return (!list2.includes(item))
})

console.log(list3)

This code snippet generates a new array (list3) from list1, removing any words that exist in list2.

Answer 8

Ensure that your variable names do not contain any spaces. When using the filter method, it requires a function as an argument and will return elements that evaluate to true when passed through that specified function.

list1 = ['carrot', 'TV', 'potato', 'laptop', 'orange', 'mouse', 'grape']
list2 = ['carrot', 'potato', 'orange', 'grape']

list3 = list1.filter(function(item) {
  return (!list2.includes(item))
})

console.log(list3)

This code snippet generates a new array (list3) from list1, removing any words that exist in list2.

Answer 9

Answer №5

let array1 = ['mango', 'iPhone', 'banana', 'computer', 'apple', 'keyboard', 'strawberry'];
let array2 = ['mango', 'banana', 'apple', 'strawberry'];

|------------|----------------------------------------------------------|
| Vanilla JS | const findDifference = (firstArray, secondArray) => firstArray.filter( item => secondArray.indexOf(item) < 0); |
|            | let output = findDifference(array1, array2);             |
|------------|----------------------------------------------------------|
| Ramda      | let output = difference(array1, array2);                |
|------------|----------------------------------------------------------|
| lodash     | let output = _.difference(array1, array2);              | 
|------------|----------------------------------------------------------|

Answer 10

let array1 = ['mango', 'iPhone', 'banana', 'computer', 'apple', 'keyboard', 'strawberry'];
let array2 = ['mango', 'banana', 'apple', 'strawberry'];

|------------|----------------------------------------------------------|
| Vanilla JS | const findDifference = (firstArray, secondArray) => firstArray.filter( item => secondArray.indexOf(item) < 0); |
|            | let output = findDifference(array1, array2);             |
|------------|----------------------------------------------------------|
| Ramda      | let output = difference(array1, array2);                |
|------------|----------------------------------------------------------|
| lodash     | let output = _.difference(array1, array2);              | 
|------------|----------------------------------------------------------|

Screen out words from one string that appear in the other

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

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