Retrieving the current window handle using Selenium WebDriver in Javascript

Question

Retrieving the current window handle using Selenium WebDriver in Javascript

After receiving assistance from engineering, I have made some modifications to my code for grabbing the new window handle. Here is the final version:

localdriver = @driver
@driver.getAllWindowHandles()
.then (handles) ->
    localdriver.switchTo().window(handles[1])

Currently, I am using a stack of automation tools that includes Selenium Webdriver, Mocha, Chai, and Grunt. My scripts are in Coffeescript, but I am open to solutions in Javascript as well.

The objective I'm aiming for is as follows:

Click on a button in the main browser window
Switch the driver to the second window that appears after clicking the button
Execute actions in the second window
Close the second window and return to the first one

I've been searching online for guidance on how to achieve this task. I started learning all these technologies just a few months ago, so I'm still navigating through the process of creating scripts. While I see many examples in Java and C++, there isn't as much in Javascript. Can someone provide an illustration of how to set up the code for the above scenario using Selenium Webdriver and Javascript?

javascript selenium coffeescript

Answer 1

Answer №1

let parentWindow = driver.getWindowHandle();
let allWindows = driver.getAllWindowHandles();

driver.switchTo().window(allWindows[1]);

// Perform some actions

driver.close();
driver.switchTo().window(parentWindow);

Answer 2

let parentWindow = driver.getWindowHandle();
let allWindows = driver.getAllWindowHandles();

driver.switchTo().window(allWindows[1]);

// Perform some actions

driver.close();
driver.switchTo().window(parentWindow);

Answer 3

Answer №2

If you're looking to retrieve all window handles in Selenium WebDriver, you should use the driver.getAllWindowHandles() method. Remember that this method returns a promise, so be sure to handle the handles within the then function.

// Select the newly opened window
driver.getAllWindowHandles().then(function gotWindowHandles(allhandles) {
    driver.switchTo().window(allhandles[allhandles.length - 1]);
});

Answer 4

If you're looking to retrieve all window handles in Selenium WebDriver, you should use the driver.getAllWindowHandles() method. Remember that this method returns a promise, so be sure to handle the handles within the then function.

// Select the newly opened window
driver.getAllWindowHandles().then(function gotWindowHandles(allhandles) {
    driver.switchTo().window(allhandles[allhandles.length - 1]);
});

Answer 5

Answer №3

When a new tab is opened, there is a delay in rendering the content. This can make it challenging to switch to the new tab because it may not be fully loaded yet and driver.getAllWindowHandles() won't return a handle for that tab. To address this issue, I have devised a solution where I assume there is one open tab already, and upon clicking a button, a new second tab is opened.

function openNewTab(driver) {
  driver.wait(function () {
    return driver.getAllWindowHandles().then(function (handles) {
      var isHandleCount2 = (handles.length == 2);
      if (isHandleCount2) {
        driver.switchTo().window(handles[1]);
      }
      return isHandleCount2;
    });
  }).then(function () {
  // Performing actions in the new tab
    var buttonElement = driver.wait(until.elementLocated(By.xpath("//td[*//span[text()='Click me']]")));
    buttonElement.click();
  });
}

This code will wait until there are exactly 2 handles or tabs before proceeding with further actions.

Answer 6

When a new tab is opened, there is a delay in rendering the content. This can make it challenging to switch to the new tab because it may not be fully loaded yet and driver.getAllWindowHandles() won't return a handle for that tab. To address this issue, I have devised a solution where I assume there is one open tab already, and upon clicking a button, a new second tab is opened.

function openNewTab(driver) {
  driver.wait(function () {
    return driver.getAllWindowHandles().then(function (handles) {
      var isHandleCount2 = (handles.length == 2);
      if (isHandleCount2) {
        driver.switchTo().window(handles[1]);
      }
      return isHandleCount2;
    });
  }).then(function () {
  // Performing actions in the new tab
    var buttonElement = driver.wait(until.elementLocated(By.xpath("//td[*//span[text()='Click me']]")));
    buttonElement.click();
  });
}

This code will wait until there are exactly 2 handles or tabs before proceeding with further actions.

Answer 7

Answer №4

@Jai Prak's answer is truly impressive.
But what happens when there are three tabs or more?
In such cases, the newest tab will always be the last one.

return await driver.wait(async function () {
    return await driver.getAllWindowHandles().then(async function (handles) {
       // var isHandleCount2 = (handles.length == 2);
        if (handles.length > 1) {
            return driver.switchTo().window(handles[handles.length - 1]);
        }
        return false;
    });
}).then(function () {
    // Now perform some actions in the new tab

});

The above logic holds true except when you switch between Tabs.
To navigate to the next tab, simply subtract 1 from the index of the current Tab.

Answer 8

@Jai Prak's answer is truly impressive.
But what happens when there are three tabs or more?
In such cases, the newest tab will always be the last one.

return await driver.wait(async function () {
    return await driver.getAllWindowHandles().then(async function (handles) {
       // var isHandleCount2 = (handles.length == 2);
        if (handles.length > 1) {
            return driver.switchTo().window(handles[handles.length - 1]);
        }
        return false;
    });
}).then(function () {
    // Now perform some actions in the new tab

});

The above logic holds true except when you switch between Tabs.
To navigate to the next tab, simply subtract 1 from the index of the current Tab.

Retrieving the current window handle using Selenium WebDriver in Javascript

Answer №1

Answer №2

Answer №3

Answer №4

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