Is there a way to extract all parts of a URL after "/"? For example:
http://myadress.com/#/example/url/here/param1
Result: ['example', 'url', 'here'].
Currently, $routeParams only returns an object with route parameters like {param1: 'param1'}
What is the best approach to achieve this?
Extracting parts of a URL can be done in the following way:
var urlParts = window.location.pathname.split( '/' );
This code snippet will allow you to retrieve specific information from the URL string.
var secondLevelLocation = urlParts[0];
Instead of following Jo_bast's suggestion, another option could be utilizing the hash instead of the pathname, as the hash will initiate after the /#/.
Both approaches are valid, just differing methods of incorporating $window.location. By utilizing the hash method, you can avoid dealing with the path preceding the hash(#) in the URL.
var path = $window.location.hash.split('/');
var path1 = path[1]; //example;
var path2 = path[2]; //url;
and so forth...
It's important to keep in mind that Angular is essentially JavaScript. You have the flexibility to utilize native JavaScript functions for various tasks.
For more information, take a look at the location documentation.
If you need to extract the pathname from the URL, you can leverage location.pathname.
// Example URL: http://myadress.com/#/example/url/here/param1
location.pathname.split('/') // --> ['', '#', 'example', 'url', 'here', 'param1']
To manipulate URLs in AngularJS, you can leverage the $location service:
var urlSegments = $location.path().split('/');
// Remove the initial empty segment
urlSegments.splice(0, 1);
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