Retrieve the latest entry from a JSON file containing epoch timestamps

Currently, I am in the process of developing an app using angularjs. In my json data, I have timestamps and corresponding values like below:

{
    "dps": {
      "1455719820": 0,
      "1455720150": 0,
      "1455720480": 0,
      "1455720810": 0,
      "1455721140": 0,
      "1455721470": 0,
      "1455721800": 0,
      "1455722130": 0
    }
  }

My dilemma lies in figuring out how to extract the value associated with the most recent timestamp from this json data structure. Any advice or insights would be greatly appreciated.

javascriptangularjsjson

Answer №1

A method that I find highly compatible and easy to understand is as follows:

  1. Start by using the Object.keys
  2. If necessary, you can proceed to sort() them (although in this particular example, sorting isn't needed)
  3. Retrieve the value (which is always 0 in this case) by either using pop or arr[arr.length-1]

var o = {
    "dps": {
      "1455719820": 10,
      "1455720150": 90,
      "1455720480": 110,
      "1455720810": 560,
      "1455721140": 670,
      "1455721470": 120,
      "1455721800": 9,
      "1455722130": 130
    }
  }

// Just for sorting purposes
var arr = Object.keys(o.dps).sort(); // Your keys were actually already sorted
console.log(arr);

// To obtain the latest value:
var newest = arr.pop();
var val = o.dps[newest];
console.log(newest,val)

Answer №2

 let largestTimestamp = 0;
 let dataObj = {
    "dps": {
      "1455719820": 0,
      "1455720150": 0,
      "1455720480": 0,
      "1455720810": 0,
      "1455721140": 0,
      "1455721470": 0,
      "1455721800": 0,
      "1455722130": 0
    }
  }
for(let key in dataObj.dps){
    if(largestTimestamp < key){
          largestTimestamp = key;
    }
}

// largestTimestamp now holds the biggest timestamp

Answer №3

To achieve this task, you can utilize Array#reduce. This method allows for a single loop operation without the need to sort keys beforehand.

var data = { "dps": { "1455719820": 0, "1455720150": 0, "1455720480": 0, "1455720810": 0, "1455721140": 0, "1455721470": 0, "1455721800": 0, "1455722130": 42 } },
    result = data.dps[Object.keys(data.dps).reduce(function (r, a) {
        return r < a ? a : r;
    }, 0)];

console.log(result);

Answer №4

var obj = {
  "values": {
    "1455719820": 0,
    "1455720150": 0,
    "1455720480": 0,
    "1455720810": 0,
    "1455721140": 0,
    "1455721470": 0,
    "1455721800": 0,
    "1455722130": 0
  }
}

var maxValue = Math.max.apply(Math, Object.keys(obj.values));

console.log(maxValue);

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