Retrieve a non-existent property from an object using the forEach method

Within my data array, I have a collection of objects with varying properties. Some objects may have all the properties while others might be missing certain ones.

const data = [
      {
        car: 12,
        airplane: 42,
        peoples: 2,
      },
      {
        car: 12,
        peoples: 2,
      },
      {
        car: 12,
        airplane: 42,
        peoples: 2,
      },
    ];

I am looking to use a filter() method to filter out objects based on a specific condition. The challenge arises when some objects do not have all required properties, leading to code errors. How can I handle this situation without causing the code to break?

data.forEach((item) => item.airplane > 5);

Answer №1

Applying Array#filter:

const info = [ { car: 10, airplane: 35, people: 4 }, { car: 15, people: 6 }, { car: 20, airplane: 45, people: 8 } ];

const result = info.filter(({ airplane }) => airplane && airplane > 20);

console.log(result);

Answer №2

To streamline your approach, consider utilizing both optional chaining (?.) and the nullish coalescing operator (??). By combining these two methods, you can implement a fallback option when a property in the chain is missing. Here's how you could modify your callback:

(item) => (item?.airplane ?? 0) > 5

If the property item.airplane exists, the calculation will proceed as expected. However, if it is absent, the condition will default to evaluating 0 > 5.

Answer №3

To efficiently filter through your data, remember to incorporate the filter() method along with a detailed filter criteria based on the property -

const filteredData = data.filter((item) => item.airplane && item.airplane > 5)

Answer №4

To verify the presence of the item within your function, you may utilize the following approach:

const outcome = data.filter(function(item) {
  if (item.airplane) {
    return item.airplane > 5;
  } else {
    return false;
  }
});

This method remains functional even when strict mode is enforced.

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