I am curious about the outcome of this code in JavaScript and would like to understand it better. When I use the following code, it produces these results:
var a =[1][1];
var b = [1][0];
if(a){console.log(true);}else{console.log(false);} --> returns false
if(b){console.log(true);}else{console.log(false);} --> returns true
Can someone explain in detail how JavaScript interprets these results?
Let's dive into it in a simpler way:
var x = [0][0];
If we break it down, we get:
var x = [0]; // Creates an array with the value '0' at index 0
x = x[0]; // Assigns x the value at index 0, which is '0'
Similar to y, but y references index 1, which contains a value of 3;
x is equal to 0, considered falsy, while y holds the value 3, making it truthy.
Essentially, you are fetching the value from an array that only contains 1.
a will be assigned undefined because there is no element at index 1.
On the other hand, b will be assigned 1 due to the presence of 1 at index 0.
var a = [1][1]; // undefined
var b = [1][0]; // 1
console.log(a); // undefined
console.log(b); // 1
if (a) {
console.log(true);
} else {
console.log(false); // false
}
if (b) {
console.log(true); // true
} else {
console.log(false);
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