Removing the initial item added to an array in Lowdb

I've been working with lowdb to remove an object from a list

{
  "posts": [
    { "id": a, "title": "lowdb is awesome"},
    { "id": b, "title": "lowdb is awesome"},
    { "id": c, "title": "lowdb is awesome"}
  ],
  "user": {
    "name": "typicode"
  },
  "count": 3
}

and now I'm trying to find a way to "pop" the first inserted object from posts:

db.get('posts')
  .find()
  .value()

My expectation is that this will return

{ "id": a, "title": "lowdb is awesome"}
and the posts array will be updated accordingly

Answer №1

To remove the initial element of an array, you can easily accomplish this by employing the shift() function. Remember, the pop() function eliminates the final item in the array.

Answer №2

To retrieve the first element from an array, you can utilize shift().

By using this method, you can eliminate the initial element in the array and obtain it as a result.

For a better understanding of how shift() functions, experiment with the following code:

let a = [ {"a":1}, {"b":2}, {"c":3} ];

// Displays [ {"a":1}, {"b":2}, {"c":3} ]
console.log(a);

// The top element from array 'a' is removed and stored in 'topItem'
let topItem = a.shift();

// Displays {"a":1}
console.log(topItem);

// Displays [ {"b":2}, {"c":3} ]
console.log(a);

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