Is there a way to replace Latex characters following the {\'<1 alpha>} pattern with their corresponding English letter?
For instance:
L{\'o}pez
Would become:
Lopez
This replacement should only target characters within the {\'<1 alpha>} pattern and should be thorough as there could be multiple characters that need to be substituted.
$1 was specifically designed for this purpose:
var new_string = 'L{\\\'o}pez'.replace(/\{\\['"]([A-Z])\}/gi, '$1');
The additional \ characters are included to properly escape the \ and the '.
\{ Identifies a {
\\ Represents a \
(?: Begins a non-capturing group
\' Matches a single quote
| OR
\" Matches a double quote
) Ends the group
([A-Z]) Captures a single alphabetical character in a group
\} Indicates the end of the selection
g: Replaces multiple occurrences
i: Enables case-insensitive matching. [A-Z] is interpreted as: [A-Za-z]
{\\'([a-zA-Z])}
Give this a shot. Substitute with $1. Check out the demo.
https://regex101.com/r/oF9hR9/3
var re = /{\\'([a-zA-Z])}/g;
var str = 'L{\'o}pez';
var subst = '$1';
var result = str.replace(re, subst);
If you need to extract a specific character from a string, you can achieve this using regex.
var str = "L{\'o}pez";
var res = str.replace(/{\\'([a-zA-Z])}/g, /$1/);
The \S will identify an alphabetical character and then the replace function will substitute the matched regex /{\'([a-zA-Z])}/g with the first group $1, which represents the character ([a-zA-Z]).
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