Remove the JSON key from all array elements while preserving their child elements

Question

Remove the JSON key from all array elements while preserving their child elements

I have an array of JSON objects that looks like this:

var array_json = [{"my":{"id":144,"price":12500000}},
{"my":{"id":145,"price":13500000}},{"my":{"id":146,"price":13450000}},
{"my":{"id":147,"price":11500000}},{"my":{"id":148,"price":15560000}}]

My goal is to remove the "my" key from each object while keeping the other information intact. Essentially, I want it to look like this:

array_json = [{"id":144,"price":12500000},{"id":145,"price":13500000},
{"id":146,"price":13450000},{"id":147,"price":11500000},
{"id":148,"price":15560000}]

Is there a way to achieve this?

Thank you.

javascript arrays json

Answer 1

Answer №1

If you want to manipulate an array in JavaScript, you can utilize the map method:

var array_json = [{"my":{"id":144,"price":12500000}},
  {"my":{"id":145,"price":13500000}},{"my":{"id":146,"price":13450000}},
  {"my":{"id":147,"price":11500000}},{"my":{"id":148,"price":15560000}}];
    
array_json = array_json.map( function( value ) {
  return value.my;
});
    
console.log( array_json )

Answer 2

If you want to manipulate an array in JavaScript, you can utilize the map method:

var array_json = [{"my":{"id":144,"price":12500000}},
  {"my":{"id":145,"price":13500000}},{"my":{"id":146,"price":13450000}},
  {"my":{"id":147,"price":11500000}},{"my":{"id":148,"price":15560000}}];
    
array_json = array_json.map( function( value ) {
  return value.my;
});
    
console.log( array_json )

Answer 3

Answer №2

JavaScript

This code snippet demonstrates how to iterate through an array and update each index with the value of a specific property.

for (let i = 0; i < array_json.length; i++) {
    array_json[i] = array_json[i].my;
}

Answer 4

JavaScript

This code snippet demonstrates how to iterate through an array and update each index with the value of a specific property.

for (let i = 0; i < array_json.length; i++) {
    array_json[i] = array_json[i].my;
}

Answer 5

Answer №3

Here is a code snippet that you can use:

    var array_json = [
        {"my":{"id":144,"price":12500000}},
        {"my":{"id":145,"price":13500000}},
        {"my":{"id":146,"price":13450000}},
        {"my":{"id":147,"price":11500000}},
        {"my":{"id":148,"price":15560000}}
    ];
    var objs= new Object(); 
   for (x in array_json) {
       objs[x]=array_json[x].my;
       alert(objs[x].id);
       alert(objs[x].price);
}

After running the code, the result will be stored in the 'objs' variable as shown below:

objs=[
      {"id":144,"price":12500000}},
      {"id":145,"price":13500000}},
      {"id":146,"price":13450000}},
      {"id":147,"price":11500000}},
      {"id":148,"price":15560000}}
]

You can test the code on this JSFiddle link.

Answer 6

Here is a code snippet that you can use:

    var array_json = [
        {"my":{"id":144,"price":12500000}},
        {"my":{"id":145,"price":13500000}},
        {"my":{"id":146,"price":13450000}},
        {"my":{"id":147,"price":11500000}},
        {"my":{"id":148,"price":15560000}}
    ];
    var objs= new Object(); 
   for (x in array_json) {
       objs[x]=array_json[x].my;
       alert(objs[x].id);
       alert(objs[x].price);
}

After running the code, the result will be stored in the 'objs' variable as shown below:

objs=[
      {"id":144,"price":12500000}},
      {"id":145,"price":13500000}},
      {"id":146,"price":13450000}},
      {"id":147,"price":11500000}},
      {"id":148,"price":15560000}}
]

You can test the code on this JSFiddle link.

Remove the JSON key from all array elements while preserving their child elements

Answer №1

Answer №2

JavaScript

Answer №3

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