I need to remove the initial 6 characters (numbers) from a number and verify if it matches any number on a given list.
For instance, if we have a number input like:
1234567891234567
The first 6 characters extracted would be:
123456
Then I want to confirm if 123456 is equal to any of these numbers: 123456|765321|988721.
To extract the first n digits, I can use this pattern: \d{6}. After that, I'll need to verify if those 6 digits match one of the numbers in the list.
To ensure that the regular expression matches only at the start of the string, you can include a start of string anchor ^.
const regexp = /^(123456|765321|988721)/;
console.log(regexp.test('1234567891234567'));
console.log(regexp.test('7653217891234567'));
console.log(regexp.test('qq'));When you have already extracted the 6 digits from the beginning of a string using ^\d{6}, you can then utilize the split method and iterate through the values like this:
"123456|765321|988721".split('|').forEach((s) => {
console.log(s === "123456");
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