Is there a way to filter this array to only include objects with truthy values for keys? For example, here is an array:
[
{ foo: NaN, test: 'String' },
{ foo: 2, test: '' },
{ foo: 3, test: 'Something' },
]
I want to create a new array that excludes objects with falsy values for keys. So, in this case, the new array should only contain the third object:
[
{ foo: 3, test: 'Something' },
]
Simply go through each object and filter out those without empty values.
var array = [{ foo: NaN, test: 'String' }, { foo: 2, test: '' }, { foo: 3, test: 'Something' }],
result = array.filter(o => Object.values(o).every(Boolean));
console.log(result);Utilize the filter and reduce methods to achieve the desired outcome
const items = [
{ bar: Infinity, trial: 'Text' },
{ bar: 5, trial: 'Another' },
{ bar: 6, trial: 'Nothing' },
]
items.filter(item => Object.values(item).reduce((accumulator, value) => accumulator && value), true)
Iterate through your array and include a condition as shown below:
var array = [
{ bar: NaN, sample: 'Text' },
{ bar: 5, sample: 'Testing' },
{ bar: 7, sample: 'Example' },
]; // sample data
var updatedArray=[];
for(var x=0;x<array.length;x++){
if(array[x].bar && array[x].sample){
updatedArray.push( array[x]);
}
}
Bar = 2 is not falsy in this instance, therefore it is also present in the final result.
const data = [
{ bar: NaN, test: 'String' },
{ bar: 2, test: '' },
{ bar: 3, test: 'Something' },
];
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