Remove element in array[x] removes the value without deleting the entire element

I encountered an issue with an object that contains duplicate values. To address this, I tried using delete new_object[1] to remove the value. However, upon checking the console, the object 0800 displayed "undefined".

["293", undefined, "298", "297"]

Answer №1

It is recommended to use

arr.splice(index, 1);

The delete function merely removes the element but retains the indexes. For more insights on this topic, you can refer to this related question.

Answer №2

In my opinion, it would be beneficial for you to implement the splice method in this scenario.

arr = ["apple", "orange", "banana"];
arr.splice(1, 0);
console.log(arr) //["apple", "banana"]

Answer №3

let array = [5,6,7,8];

remove element at index 1 in the array

if you console log the array variable, you will see

=> [ 5, , 7, 8 ]

this is why you are getting undefined

as many have suggested before, use splice method instead

array.splice(1,1);

now when you print the array variable, you will get

=> [ 5, 7, 8, 9 ]

Answer №4

To properly remove a value from an array, you should utilize the splice() method instead of simply setting it to undefined.

var myArray = ['100', '200', '300', '400'];

// removes 1 element from index 2
var removed = myArray.splice(2, 1);
// myArray now contains ['100', '200', '400'];
// The removed element is '300'

For more information, check out the documentation on Array.splice

The splice() method is used to modify the content of an array by removing existing elements or adding new ones.

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