Remove a field from a JSON array

Question

Remove a field from a JSON array

Consider the following JSON array:

var arr = [
{ID: "1", Title: "T1", Name: "N1"}, 
{ID: "2", Title: "T2", Name: "N2"}, 
{ID: "3", Title: "T3", Name: "N3"}
]

Is there a way to remove the Title key from all rows simultaneously without using a loop?

The resulting array should be:

var arr = [
{ID: "1", Name: "N1"}, 
{ID: "2", Name: "N2"}, 
{ID: "3", Name: "N3"}
]

I attempted the code below:

delete arr.Title

But it only returns a logical response of "true" instead of the updated array.

javascript arrays json

Answer 1

Answer №1

you were not too far off:

[edit] consider these alternative solutions: 1) Implement forEach or for..of loop. 2) Use delete or Reflect.deleteProperty method.

let
  arr_1 = [
    {ID: 1, Title: "T1", Name: "N1"},
    {ID: 2, Title: "T2", Name: "N2"},
    {ID: 3, Title: "T3", Name: "N3"}
  ],
  arr_2 = arr_1.map(e=>Object.assign({},e)) // create a new array of copies
;

// solution 1
arr_1.forEach(elm=>delete elm.Title)

// solution 2
for(let elm of arr_2){ Reflect.deleteProperty(elm, 'Name') } // update

console.log('arr_1 =', JSON.stringify(arr_1))
console.log('arr_2 =', JSON.stringify(arr_2))

Answer 2

you were not too far off:

[edit] consider these alternative solutions: 1) Implement forEach or for..of loop. 2) Use delete or Reflect.deleteProperty method.

let
  arr_1 = [
    {ID: 1, Title: "T1", Name: "N1"},
    {ID: 2, Title: "T2", Name: "N2"},
    {ID: 3, Title: "T3", Name: "N3"}
  ],
  arr_2 = arr_1.map(e=>Object.assign({},e)) // create a new array of copies
;

// solution 1
arr_1.forEach(elm=>delete elm.Title)

// solution 2
for(let elm of arr_2){ Reflect.deleteProperty(elm, 'Name') } // update

console.log('arr_1 =', JSON.stringify(arr_1))
console.log('arr_2 =', JSON.stringify(arr_2))

Answer 3

Answer №2

An alternative method involves using the map function to generate a new array with the desired output. Within the handler, a new Object is created using the object from each index, and then the unwanted property name Title is removed.

If you were referring to an array, this approach ensures that the original objects remain unchanged.

let arr = [{ID: "1", Title: "T1", Name: "N1"}, {ID: "2", Title: "T2", Name: "N2"}, {ID: "3", Title: "T3", Name: "N3"}],
    result = arr.map(o => {
      let obj = Object.assign({}, o);
      delete obj.Title;
      return obj;
    });

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 4

An alternative method involves using the map function to generate a new array with the desired output. Within the handler, a new Object is created using the object from each index, and then the unwanted property name Title is removed.

If you were referring to an array, this approach ensures that the original objects remain unchanged.

let arr = [{ID: "1", Title: "T1", Name: "N1"}, {ID: "2", Title: "T2", Name: "N2"}, {ID: "3", Title: "T3", Name: "N3"}],
    result = arr.map(o => {
      let obj = Object.assign({}, o);
      delete obj.Title;
      return obj;
    });

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 5

Answer №3

If you're aiming to avoid using a loop in your code, there are alternative approaches we can take. While JavaScript doesn't provide a direct method for mass operations on list elements like some other languages do, such as APL and K, we can utilize tools like map to abstract the looping process. However, it's important to note that even when using map, there is still an underlying looping mechanism at play.

var arr = [
  {ID: "1", Title: "T1", Name: "N1"}, 
  {ID: "2", Title: "T2", Name: "N2"}, 
  {ID: "3", Title: "T3", Name: "N3"}
]

const newArr = arr.map(({Title, ...rest}) => ({...rest}))

console.log(newArr)

Answer 6

If you're aiming to avoid using a loop in your code, there are alternative approaches we can take. While JavaScript doesn't provide a direct method for mass operations on list elements like some other languages do, such as APL and K, we can utilize tools like map to abstract the looping process. However, it's important to note that even when using map, there is still an underlying looping mechanism at play.

var arr = [
  {ID: "1", Title: "T1", Name: "N1"}, 
  {ID: "2", Title: "T2", Name: "N2"}, 
  {ID: "3", Title: "T3", Name: "N3"}
]

const newArr = arr.map(({Title, ...rest}) => ({...rest}))

console.log(newArr)

Answer 7

Answer №4

When working with actual JSON strings, you can utilize the JSON.parse reviver parameter to filter or modify values :

var jsonData = '[{"ID":"1","Title":"T1","Name":"N1"},{"ID":"2","Title":"T2","Name":"N2"},{"ID":"3","Title":"T3","Name":"N3"}]'

var filteredArray = JSON.parse(jsonData, (key, value) => key != 'Title' ? value : void 0);

console.log( filteredArray );

Answer 8

When working with actual JSON strings, you can utilize the JSON.parse reviver parameter to filter or modify values :

var jsonData = '[{"ID":"1","Title":"T1","Name":"N1"},{"ID":"2","Title":"T2","Name":"N2"},{"ID":"3","Title":"T3","Name":"N3"}]'

var filteredArray = JSON.parse(jsonData, (key, value) => key != 'Title' ? value : void 0);

console.log( filteredArray );

Answer 9

Answer №5

The arr variable is mistakenly identified as an array, but it is actually an object.
Objects in JavaScript are enclosed in curly braces {}, such as:

{ "name":"Bob", "alive":true, "dead":false }

Arrays, on the other hand, are enclosed in square brackets [], like this: ["Bob","Jane","Mary"]

Answer 10

The arr variable is mistakenly identified as an array, but it is actually an object.
Objects in JavaScript are enclosed in curly braces {}, such as:

{ "name":"Bob", "alive":true, "dead":false }

Arrays, on the other hand, are enclosed in square brackets [], like this: ["Bob","Jane","Mary"]

Answer 11

Answer №6

One effective approach is to utilize functional utilities that simplify the process of solving problems.

import { map, omit } from 'lodash/fp';
const modifiedArray = map(omit('Title'), originalArray);

Answer 12

One effective approach is to utilize functional utilities that simplify the process of solving problems.

import { map, omit } from 'lodash/fp';
const modifiedArray = map(omit('Title'), originalArray);

Remove a field from a JSON array

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

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