Regular expression validation to separate phone numbers and country codes

As a beginner in writing regex, I have been tasked with creating a phone number validation system. Currently, it's proving to be quite challenging for me.

My progress so far:

^([+]45|[(][+]45[)]?|[(]0045[)]|0045)?\s*([0-9]{8})$

I need to accomplish two things:

  1. Country code. The country code can be written in different formats.

    1. With a plus before the country code
    2. With a plus before the country code enclosed in parentheses
    3. With 00 before the country code
    4. With 00 before the country code enclosed in parentheses
  2. The Phone number The phone number is always assumed to be from my country, hence the consistent country code.

The challenge arises when using 00 for the country code. While I want to enforce an 8-digit phone number requirement, if the country code is 0045, only 4 digits are needed for a "true" result.

I'm struggling to ensure this condition is met. Is there a feasible way to achieve this?

Answer №1

To find an 8-digit phone number without the prefix, you can look for patterns like +45 or (45) or (0045) or 0045 followed by 8 digits.

You can also search for 8 digits that do not begin with '00' to indicate a country code using a negative lookahead syntax like (?!00)

^(?:\+45|\(\+45\)|\(0045\)|0045|(?!00))\d{8}$

Description:

  • ^ Indicates the start of the string
  • (?: Non-capturing group
    • \+45|\(\+45\)|\(0045\)|0045|(?!00)
      Matches any of these options or ensures '00' is not at the beginning
  • ) Closes the non-capture group
  • \d{8} Matches 8 digits
  • $ Denotes the end of the string

Try the Regex here

Answer №2

I've modified the expression to: ^(^([+]45|[(][+]45[)]?|[(]0045[)]|0045)?\s*([1-9]{1})([0-9]{7})$

This solution currently serves my needs

However, more robust solutions may be necessary in the future, especially if international numbers are to be included at a later time.

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