I'm trying to figure out a way to count the number of digits in a string that resembles a password.
Currently, I am using this regular expression:
^(?=.*[0-9]{3,})([a-zA-Z0-9_/+*.-]{6,})$
It works well when there are 3 consecutive digits, but not when they are scattered throughout the entire string.
I want to be able to detect if there are 3 digits in strings like these:
h123dasd 1hkh/23jd 1gvbn/*2fefse-
How can I achieve this?
If you're looking to verify the presence of at least 3 digits in your input, regardless of whether they are consecutive or not, you can use the following regular expression:
/^(?=(?:\D*\d){3,})[a-zA-Z0-9_/+*.-]{6,}$/
This regex pattern will ensure that there are at least 3 digits included in the input.
I believe there is no necessity for a complex regex in this case - simply extract the digits from the string, combine the matches, and then verify the length. Here is an example:
str.match(/\d+/g).reduce((previous, current) => previous + current).length > 3;
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