I'm really struggling with this algorithm. It needs to be recursive, but I can't seem to crack it. Any help would be greatly appreciated. Thank you!
Here is the problem: ['a','b','c',['d','e','f',['g','h']], [i, j, k]]
Desired Output:
{
a: true,
b: true,
c: true,
d: {
e: true,
f: true,
g: {
h: true
}
},
i: {
j: true,
k: true
}
}
To convert an array to an object, you can utilize the Object.fromEntries method by providing key/value pairs. If the "key" is actually an array, extract the first element as the key and recursively process the rest of the array to generate the corresponding value:
const toObject = arr =>
Object.fromEntries(arr.map(item => Array.isArray(item)
? [item[0], toObject(item.slice(1))]
: [item, true]
));
const arr = ["a", "b", "c", ["d", "e", "f", ["g", "h"]], ["i", "j", "k"]];
const result = toObject(arr);
console.log(result);Here is an example of using the Array#reduce method:
const transform = (arr = []) =>
arr.reduce((acc, elem) => {
if (Array.isArray(elem)) {
const [key, ...rest] = elem;
acc[key] = transform(rest);
} else {
acc[elem] = true;
}
return acc;
}, {});
console.log(
transform(["apple", "banana", "cherry", ["date", "elderberry", "fig", ["grape", "honeydew"]], ["imbe", "jackfruit", "kiwi"]])
);In Ruby (imagine this as a simplified code).
def convert(arr)
arr.each_with_object({}) do |element, hash|
case element
when String
hash[element.to_sym] = true
else # Array
hash[element.first.to_sym] = convert(element.drop(1))
end
end
end
Imagine a scenario (slightly altered from the original example)
arr = ['a','b','c',['d','e','f',['g','h', ['m', 'n']]], ['i', 'j', 'k']]
The output will be:
convert arr
#=> {
# :a=>true,
# :b=>true,
# :c=>true,
# :d=> {
# :e=>true,
# :f=>true,
# :g=>{
# :h=>true,
# :m=>{
# :n=>true
# }
# }
# },
# :i=>{
# :j=>true,
# :k=>true
# }
# }
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