Quick method for updating the contents of an array

Is there a way to replace the content of an array and still maintain a reference to it without losing the original reference? I want to avoid simply reassigning the array like this:

var arr1 = [1,2,3];
var referenceToArr1 = arr1;
var arr2 = [4,5,6];

arr1 = arr2;
// logs: [4,5,6] false
console.log(arr1, arr1===referenceToArr1);
// logs [1,2,3]
console.log(referenceToArr1);

In this scenario, arr1 is updated with the contents of arr2, but the reference in referenceToArr1 is lost as it still points to the original arr1.

To preserve the reference, you can do it like this:

var arr1 = [1,2,3];
var referenceToArr1 = arr1;
var arr2 = [4,5,6];

arr1.length = 0;
for (var i = 0; i < arr2.length; i++) {
  arr1.push(arr2[i]);
}
// logs: [4,5,6] true
console.log(arr1, arr1===referenceToArr1);
// logs: [4,5,6]
console.log(referenceToArr1)

The downside here is that you need to clear arr1.length = 0, iterate through each element of arr2, and manually push them into arr1.

Some questions to consider:

  • Could a helper function make this process more efficient?
  • Is there a concise vanilla JavaScript solution for this task (possibly a one-liner)?
  • I use underscore.js but haven't found a method for this. Can underscore.js help in this situation?

Context:

I am working on an AngularJS app involving a service that contains an array holding data fetched from a server. This data is bound to a controller and displayed in a view. When the service data is updated (e.g., due to a refetch), I want the controller variables and the linked view to update automatically.

Check out the Plunker example here: http://plnkr.co/edit/8yYahwDO6pAuwl6lcpAS?p=preview

var app = angular.module('plunker', []);

app.controller('MainCtrl', function($scope, myService) {
  $scope.name = 'World';
  myService.fetchData().then(function(data) {
    console.log(data)
    $scope.data = data;
  })
});

app.service('myService', function($timeout, $q) {
  var arr;
  var deferred;

  var loadData = function() {
    // Data comes from the server here
    var serverData = [1,2,3];
    arr = serverData;
    deferred.resolve(arr);

    // Simulate a data refetch
    $timeout(function() {
      var newServerData = [4,5,6];
      // Reassigning won't work as the MainCtrl loses its reference
      // arr = newServerData;
    }, 1000);

    $timeout(function() {
      var newServerData = [7,8,9];
      arr.length = 0;
      [].push.apply(arr, newServerData);
    }, 2000);

    $timeout(function() {
      var newServerData = [10,11,12];
      [].splice.apply(arr, [0, arr.length].concat(newServerData));
    }, 3000);
  }

  return {
    fetchData: function() {
      deferred = $q.defer();

      loadData();

      return deferred.promise;
    }
  }
})

View code:

<!DOCTYPE html>
<html ng-app="plunker">

  <head>
    <meta charset="utf-8" />
    <title>AngularJS Plunker</title>
    <script>document.write('<base href="' + document.location + '" />');</script>
    <link rel="stylesheet" href="style.css" />
    <script data-require="<a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="7c1d121b09101d0e52160f3c4d524e5204">[email protected]</a>" src="https://code.angularjs.org/1.2.16/angular.js" data-semver="1.2.16"></script>
    <script src="app.js"></script>
  </head>

  <body ng-controller="MainCtrl">
    <ul>
      <li ng-repeat="d in data">{{d}}</li>
    </ul>
    3 refetches every second
  </body>

</html>

Answer №1

What do you think of this solution:

// 1. Clear the contents of a given array without changing its reference
arr1.length = 0;
// 2. Populate the first array with elements from the second array
[].push.apply(arr1, arr2);

References:

  1. Effective ways to reset an array in JavaScript
  2. Resolving issues with pushing multiple objects into JavaScript arrays resulting in 'undefined'

Answer №2

To update the content of arr1 with that of arr2, you can utilize the splice method:

[].splice.apply(arr1, [0, arr1.length].concat(arr2));

This operation ensures that all references to arr1 are accurately updated, maintaining consistency within the array.

While this method is feasible and straightforward, it is typically unnecessary in a properly structured program. If you find yourself needing to pass an array to multiple locations, consider encapsulating the array within an object instead.

Answer №3

Combining both arrays while keeping items from the second array

[...array2, ...array1.slice(array2.length)]

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