Proper Techniques for Parsing JSON Data

Question

Proper Techniques for Parsing JSON Data

Currently, I am utilizing the PokeAPI. My approach involves making fetch requests to obtain JSON data from a specific endpoint, and then attempting to parse and return it. The function responsible for this task can be located below:

function getPokemon(id){

    pokemonData = {
        name:"",
        image:"",
        id:id,
        description:""
    }
    
    // Documentation: https://pokeapi.co/docs/v2#pokemon-species
    fetch(`https://pokeapi.co/api/v2/pokemon-species/${id}/`)
      .then((response) => response.json())
          .then((data) => {
        
            pokemonData.description = data.flavor_text_entries[0].flavor_text.toString()
            
          }
        )
    
    // Documentation: https://pokeapi.co/docs/v2#pokemon
    fetch(`https://pokeapi.co/api/v2/pokemon/${id}/`)
      .then((response) => response.json())
          .then((data) => {
        
            pokemonData["image"] = data.sprites.other["official-artwork"].front_default.toString()
            pokemonData["name"] = data.name.toString()
            
          }
        )

    return pokemonData
}

After receiving the data, my attempts to access attributes show blank values, despite the object displaying the correct information:

https://i.sstatic.net/a15KY.png

I am uncertain about what is going wrong in this scenario. I have experimented with various attribute access formats such as data.name versus data["name"], but none seem to have an impact. Any assistance on this matter would be greatly appreciated.

javascript fetch-api

Answer 1

Answer №1

Your solution is accurate for solving the problem at hand, although it could benefit from a more efficient use of `async / await` and promises.

To optimize the code, consider using `await` on both `fetch` calls to run the requests simultaneously instead of sequentially. This can be achieved by allowing both `fetch` calls to execute in parallel and waiting for both to complete using `Promise.all()`.

Once both requests have been fulfilled, you can construct your `pokemonData` object based on the data retrieved from each source.

async function getPokemon(id) {
  const speciesRequest = fetch(`https://pokeapi.co/api/v2/pokemon-species/${id}/`)
    .then((response) => response.json())
    
  const pokemonRequest fetch(`https://pokeapi.co/api/v2/pokemon/${id}/`)
    .then((response) => response.json())
  
  try {
    const [speciesData, pokemonData] = await Promise.all([speciesRequest, pokemonRequest]);

    return ({
      id,
      image: pokemonData.sprites.other["official-artwork"].front_default,
      name: pokemonData.name,
      description: speciesData.flavor_text_entries[0].flavor_text.toString()
    });
  catch (error) {
    return Promise.reject(error);
  }
}

Answer 2

Your solution is accurate for solving the problem at hand, although it could benefit from a more efficient use of `async / await` and promises.

To optimize the code, consider using `await` on both `fetch` calls to run the requests simultaneously instead of sequentially. This can be achieved by allowing both `fetch` calls to execute in parallel and waiting for both to complete using `Promise.all()`.

Once both requests have been fulfilled, you can construct your `pokemonData` object based on the data retrieved from each source.

async function getPokemon(id) {
  const speciesRequest = fetch(`https://pokeapi.co/api/v2/pokemon-species/${id}/`)
    .then((response) => response.json())
    
  const pokemonRequest fetch(`https://pokeapi.co/api/v2/pokemon/${id}/`)
    .then((response) => response.json())
  
  try {
    const [speciesData, pokemonData] = await Promise.all([speciesRequest, pokemonRequest]);

    return ({
      id,
      image: pokemonData.sprites.other["official-artwork"].front_default,
      name: pokemonData.name,
      description: speciesData.flavor_text_entries[0].flavor_text.toString()
    });
  catch (error) {
    return Promise.reject(error);
  }
}

Answer 3

Answer №2

While in the process of writing this, I had a breakthrough moment where everything suddenly made sense. Previously, I mistakenly believed that using .then() would automatically make the response synchronous as indicated by various online sources.

However, this assumption turned out to be incorrect.

To resolve the issue of my function running ahead of the fetch operation, I needed to convert my function into an async function to properly await the fetch call. The corrected code looks like this:

async function getPokemon(id){
    
    pokemonData = {
        name:"",
        image:"",
        id:id,
        description:""
    }
    
    // Documentation https://pokeapi.co/docs/v2#pokemon-species
    await fetch(`https://pokeapi.co/api/v2/pokemon-species/${id}/`)
      .then((response) => response.json())
          .then((data) => {
        
            pokemonData.description = data.flavor_text_entries[0].flavor_text.toString()
            
          }
        )
    
    // Documentation: https://pokeapi.co/docs/v2#pokemon
    await fetch(`https://pokeapi.co/api/v2/pokemon/${id}/`)
      .then((response) => response.json())
          .then((data) => {
        
            pokemonData.image = data.sprites.other["official-artwork"].front_default
            pokemonData.name = data.name
            console.log(data.name)
            
          }
        )
    return pokemonData
}

Answer 4

While in the process of writing this, I had a breakthrough moment where everything suddenly made sense. Previously, I mistakenly believed that using .then() would automatically make the response synchronous as indicated by various online sources.

However, this assumption turned out to be incorrect.

To resolve the issue of my function running ahead of the fetch operation, I needed to convert my function into an async function to properly await the fetch call. The corrected code looks like this:

async function getPokemon(id){
    
    pokemonData = {
        name:"",
        image:"",
        id:id,
        description:""
    }
    
    // Documentation https://pokeapi.co/docs/v2#pokemon-species
    await fetch(`https://pokeapi.co/api/v2/pokemon-species/${id}/`)
      .then((response) => response.json())
          .then((data) => {
        
            pokemonData.description = data.flavor_text_entries[0].flavor_text.toString()
            
          }
        )
    
    // Documentation: https://pokeapi.co/docs/v2#pokemon
    await fetch(`https://pokeapi.co/api/v2/pokemon/${id}/`)
      .then((response) => response.json())
          .then((data) => {
        
            pokemonData.image = data.sprites.other["official-artwork"].front_default
            pokemonData.name = data.name
            console.log(data.name)
            
          }
        )
    return pokemonData
}

Proper Techniques for Parsing JSON Data

Answer №1

Answer №2

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