Proceed once all .load() functions have been completed

I am encountering an issue with an asynchronous JavaScript function. I currently have a function that is inserting elements one by one, which is functioning correctly. However, my goal is to proceed only after all the .load() functions have completed.

The way I have tried to implement the Deferred() part seems to be incorrect, and I am at a loss on how to accomplish this.

Important Note: The code has been simplified for better clarity.

var d = new jQuery.Deferred();
var i = index;
function loadView() {
    if(i > -1 && i < array.length) {
        if(!jQuery.contains(document.documentElement, $(selector)[0])) {
            /* do something here */
            panel.load(myPHPfile, function() {
                $dom.append($(selector));
                i++;
                if(i < array.length) {
                    loadView();
                    d.resolve();
                }
            });
        }
    }
}
loadView();

jQuery.when(d).then(function() {
    /* execute some action once all elements are inserted */
});

Your assistance in resolving this matter would be greatly appreciated!

Answer №1

After incrementing, if i < array.length, it indicates that the task is not completed yet, so it's better not to fulfill your Deferred at that point. Consider this approach instead:

if(i < array.length) {
    loadView();
} else {                   // ***
    d.resolve();
}

Also, there's no need to utilize jQuery.when. Simply do this:

d.then(function() {
    /* perform action when all elements are inserted */
});

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