populate the empty slots in an array with the correct numbers

Having two pre-sorted arrays as shown below:

[1,2,4,5,8]
[x,x,x,x,x]

The goal is to fill in the missing elements with 'y' in the corresponding array, resulting in:

[1,2,3,4,5,6,7,8]
[x,x,y,x,x,y,y,x]

Although the data arrives separately, they always have matching sizes.

An attempt was made to achieve this task but it seems a bit complex:

function action(numbers,data){
  var len=numbers.length;
  if (len<=1){
    return [numbers,data];
  }
  var new_data=[] 
  var new_number=[] 
  for(var i=1;i<len;i++){
    var diff=numbers[i] - numbers[i-1];

    if(diff>1){
      var val=0;
      diff--;

      for(var j=0;j<diff;j++){
        val=numbers[i-1] + j +1;
        new_number.push(val)
        new_data.push('y')
      }
      new_number.push(numbers[i])
      new_data.push(data[i])
    }
  }

  new_number.unshift(numbers[0])
  new_data.unshift(data[0])

  return [new_number,new_data];
}

Despite some inconsistencies in the function, it is not completely clear.

action([2002,2005,2007],['x','x','x']) =>[2002,2003,2004,2005,2006,2007], [x,y,y,x,y,x]

However, there are still errors like the one shown below:

action([2002,2003,2007],['x','x','x']) =>[2002,2004,2005,2006,2007], [x,y,y,y,x]

The expected output should have been 2002,2003,2004,2005,2006,2007 and x,x,y,y,y,x

Update:

Adding an else statement after the diff>1 condition seems to fix the previous errors, although it's not the most elegant solution:

} else{
  new_number.push(numbers[i])
  new_data.push(data[i])
}

Answer №1

Great effort! You were almost there. Just a small tweak was needed to ensure that the original numbers are pushed to the new array every time, not just when the difference is too large.

function updateNumbers(numbers, data){
    var length = numbers.length;
    if (length <= 1){
        return [numbers, data];
    }
    var newNumbers = [] //stores updated numbers
    var newData = [] //stores new data values
    for(var i = 1; i < length; i++){
        var diff = numbers[i] - numbers[i - 1];

        if(diff > 1){
            //there is a gap here
            var value = 0;
            diff--;

            for(var j = 0; j < diff; j++){
                value = numbers[i - 1] + j + 1;
                newNumbers.push(value)
                newData.push('y')
            }
        }

        //insert current info after missing data was inserted
        newNumbers.push(numbers[i])
        newData.push(data[i])
    }

    //adjust first entry
    newNumbers.unshift(numbers[0])
    newData.unshift(data[0])

    return [newNumbers, newData];
}

console.log(updateNumbers([1, 2, 4, 5, 8], ['x', 'x', 'x', 'x', 'x']));

Answer №2

To reverse the order of elements, you can utilize a `while` loop starting from the last element and ending at the first.

var numbers = [1, 2, 4, 5, 8]
var letters = ["x", "x", "x", "x", "x"];
var index = numbers[numbers.length - 1];

while (index-- > numbers[0]) {
  if (!numbers.includes(index)) {
    var position = numbers.indexOf(index + 1)
    numbers.splice(position, 0, index);
    letters.splice(position, 0, "y");
  }
}

console.log(numbers);
console.log(letters);

Answer №3

To iterate over the elements, you can make use of forEach method:

const modifyArray = (numbers, xy) => {
  let expected = numbers[0];
  let modifiedNumbers = [];
  let modifiedXy = [];
  
  numbers.forEach((current, index) => {
    while(current > expected){
      modifiedNumbers.push(expected);
      modifiedXy.push("y");
      expected++
    }
    modifiedNumbers.push(current);
    modifiedXy.push(xy[index]);
    expected++;
  });
  
  return [modifiedNumbers, modifiedXy];
}

console.log(modifyArray(
  [1, 2, 4, 5, 8],
  ["a", "b", "c", "d", "e"]
));

Answer №4

Hopefully this information is useful. It has been demonstrated using placeholder arrays.

var array1 = [1,4,6,7,8,12,14,55];
var array2 = [2,3,5,9,13,25,27,54,56];
array2.forEach(function(value){
    var index = array1.findIndex(function(oldValue){return oldValue > value;});
    index == -1 ? array1.push(value) : array1.splice(index, 0, value);;
});
console.log(array1)

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