Pattern matching for ' ... '

I've been struggling to make a regular expression work properly: I need it to match anything that starts with 

__(' or __("

and ends with 

') or ")

I attempted using 

/__\(['"][^']*['"]\)/g  and /__\(['"].*['"]\)/g

but they both encounter issues when faced with this example text:

text that should not match
__('all text and html<a href="#">link</a> that should match') text that should not match __('all text and html<a     href="#">link</a>')
__("all text and html<a href="#">link</a>") text that should not match __("all text and html<a     href="#">link</a>")
other text that should not match

Which RegExp is the winning one?

javascriptregexregex-negation

Answer №1

Implement the non-greedy matching technique using *? in the second example and think about incorporating a backreference for the quotation marks.

/__\((['"]).*?\1\)/g

Check out the Live Demo here

Answer №2

If you're looking for a non-greedy match, the most effective solution would be to utilize the following regex:

/__\(['"][^']*?['"]\)/g

Additionally, it might be beneficial to escape both single and double quotes:

You can test this regex pattern on the following Regex101 link:

http://regex101.com/r/pT7mK2/1

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