Ordering Arrays based on a particular attribute

Question

Ordering Arrays based on a particular attribute

My array includes user points as follows:

let groupRank = [];

userA = ["Sara", "24"];
userB = ["John", "12"];
userC = ["Eddi", "20"];
userD = ["Marry", "13"];

I am looking to rank them according to their points and achieve the following result:

Console.log(groupRank);
//Sara, Eddi, Marry, John

javascript arrays

Answer 1

Answer №1

To organize the data, you can construct a 2D array and utilize the sort method to arrange it based on the points located at index 1. Then, employ the map function to extract the names that appear at index 0.

let userArray = [
  ["Sara", "24"],
  ["John", "12"],
  ["Eddi", "20"],
  ["Marry", "13"]
]

const sortedNames = userArray.sort((first, second) => second[1] - first[1])
                         .map(entry => entry[0])

console.log(sortedNames.join())

If you possess all those separate arrays in distinct variables, assemble the 2D array as follows:

let userArray = [ userA, userB, userC, userD ]

Answer 2

To organize the data, you can construct a 2D array and utilize the sort method to arrange it based on the points located at index 1. Then, employ the map function to extract the names that appear at index 0.

let userArray = [
  ["Sara", "24"],
  ["John", "12"],
  ["Eddi", "20"],
  ["Marry", "13"]
]

const sortedNames = userArray.sort((first, second) => second[1] - first[1])
                         .map(entry => entry[0])

console.log(sortedNames.join())

If you possess all those separate arrays in distinct variables, assemble the 2D array as follows:

let userArray = [ userA, userB, userC, userD ]

Answer 3

Answer №2

Begin by consolidating all arrays into one.
Next, sort the array based on the value at index 1.
Extract only the names from the array using Array#map

let groupRank = [];

userA = ["Sara", "24"];
userB = ["John", "12"];
userC = ["Eddi", "20"];
userD = ["Marry", "13"];
var res = [userA,userB,userC,userD]; //consolidate all in one
res = res.sort((a,b)=> b[1]-a[1]); // sort based on points
res = res.map(a=> a[0]); //extract the names only
console.log(res)

Answer 4

Begin by consolidating all arrays into one.
Next, sort the array based on the value at index 1.
Extract only the names from the array using Array#map

let groupRank = [];

userA = ["Sara", "24"];
userB = ["John", "12"];
userC = ["Eddi", "20"];
userD = ["Marry", "13"];
var res = [userA,userB,userC,userD]; //consolidate all in one
res = res.sort((a,b)=> b[1]-a[1]); // sort based on points
res = res.map(a=> a[0]); //extract the names only
console.log(res)

Answer 5

Answer №3

To organize the users based on their rank, you can utilize the sort function to arrange them in an array. During sorting, convert the pointer to a number using the unary operator. The result of the sort function will be an array of arrays. If you require the names only, you can employ the map function to extract the array of names.

let groupRank = [];

let userA = ["Sara", "24"];
let userB = ["John", "12"];
let userC = ["Eddi", "20"];
let userD = ["Marry", "13"];

let allUsers = [userA, userB, userC, userD];

groupRank = allUsers.sort(function(a, b) {
  return +b[1] - (+a[1])
}).map(item => item[0])


console.log(groupRank)

Answer 6

To organize the users based on their rank, you can utilize the sort function to arrange them in an array. During sorting, convert the pointer to a number using the unary operator. The result of the sort function will be an array of arrays. If you require the names only, you can employ the map function to extract the array of names.

let groupRank = [];

let userA = ["Sara", "24"];
let userB = ["John", "12"];
let userC = ["Eddi", "20"];
let userD = ["Marry", "13"];

let allUsers = [userA, userB, userC, userD];

groupRank = allUsers.sort(function(a, b) {
  return +b[1] - (+a[1])
}).map(item => item[0])


console.log(groupRank)

Ordering Arrays based on a particular attribute

Answer №1

Answer №2

Answer №3

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