Optimizing Require.js File for Efficient Loading

I have successfully implemented require.js with multiple individual files:

require(['app/login/Login'], function (app) {
   new app.Login();
});

Everything is functioning as expected, with each module loading when needed.

Recently, I have optimized my code using the Optimizer and now have a single combined .js file named "everything.js" - which is exactly what I wanted.

However, I am unsure of how to actually load this new file.

require(['everything'], function (app) {
   new app.Login();
});

When I try the above code, it returns undefined for app.

Answer №1

It turns out that the solution can be found within the optimizer documentation:

If you wish to bundle require.js with the main.js source file, you can utilize the following command:

node ../../r.js -o baseUrl=. paths.requireLib=../../require name=main include=requireLib out=main-built.js

Due to the fact that "require" is a reserved dependency name, you must create a "requireLib" dependency and associate it with the require.js file. After completing this optimization, you can update the script tag to point to "main-built.js" rather than "require.js", resulting in your optimized project only requiring one script request.

In other words, you have the ability to modify the script tag to point to "main-built.js" rather than "require.js"

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